| Benjamin Peirce - Algebra - 1855 - 308 pages
...at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
| Elias Loomis - Algebra - 1855 - 356 pages
...square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
| James Bates Thomson - Arithmetic - 1855 - 436 pages
...divisor ; multiply the divisor thus completed by the figure last placed in the root ; mbtract ttie product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <&c., as before, and thus continue... | |
| Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...divisor. IV. Multiply the divisor thus obtained by the last digit of the root found ; subtract ïhe product from the dividend, and to the remainder bring down the next period for a new dividend. If the product just found exceeds the dividend, diminish the last digit of the root found, and proceed... | |
| Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...quotient figure ; then ndd these three results together for a subtrahend. 17. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before, and so on till all the periods are brought down.* 18. NOTE. When the... | |
| Joseph Ray - Arithmetic - 1857 - 348 pages
...Multiply the complete dicisor by the last figure of the root, and subtract the product from the dividend; to the remainder bring down the next period for a...so proceed until all the periods are brought down. NOTES. — 1. When the product of the complete divisor by the last figure of the root is larger than... | |
| Charles Davies - Algebra - 1857 - 408 pages
...right of the divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root found, and subtract the product from the dividend and to...remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
| Charles Davies, William Guy Peck - Mathematics - 1857 - 608 pages
...right of the divisor. IV. Multiply the divisor thus obtained by the last digit of the root found ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. If the product just found exceeds the dividend, diminish the last digit of the root found, and proceed... | |
| Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. To the last true divisor and the number immediately over it, add the square of the last root figure,... | |
| Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
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