| Joseph Antonius Nyberg - 1924 - 378 pages
...equal fractions. Such an equation can be solved by using the idea stated in ex. 6, page 128; namely, In any proportion the product of the extremes equals the product of the means. Hence in the above proportion 306 (c + 2) = 340 c. Solve this equation and finish the problem. 136.... | |
| Lewis Parker Siceloff, David Eugene Smith - Algebra - 1924 - 274 pages
...members of the first equation by bd. This law is often expressed as follows : If four numbers are in proportion, the product of the extremes equals the product of the means. af* 2. If ad = be, then - = — • oa This is apparent if we divide both members of the first equation... | |
| Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1926 - 456 pages
...56-58.) ft (* Thus, in the proportion r = -3 both members may be multiplied by bd, giving ad = bc. Here the first member is the product of the extremes...product of the extremes equals the product of the means. EXERCISES Form proportions from the following by supplying the missing terms : 2_12 36_9 Ь 3 ~ ? '... | |
| John Charles Stone - Mathematics - 1927 - 368 pages
...becomes od ad = be by multiplying both sides of the equation by bd. In words this relation may be read : In any proportion, the product of the extremes equals the product of the means. To solve x = 15 2 10 we have 10 x = 30 EXERCISES Solve : SIMPLE PROBLEMS SOLVED BY PROPORTION Many... | |
| William Weller Strader, Lawrence D. Rhoads - Geometry, Plane - 1927 - 434 pages
...be transformed by Alternation, Inversion, Addition, Subtraction, and by any combination of them. 2. In any proportion the product of the extremes equals the product of the means. 3. If the product of two quantities equals the product of a second pair, either pair may be made the... | |
| |