 | University of Madras - 1879 - 674 pages
...MA, I. Prove that all the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. II. Prove the proposition to which the following is a corollary : The difference of the squares on... | |
 | Charles Mansford - 1879 - 112 pages
...of the other angles that the interior angles of any rectilineal figure together with 4 right angles are equal to twice as many right angles as the figure has sides. (32.) 113. If two angles have their containing sides respectively parallel to one another the lines... | |
 | Benjamin Gratz Brown - Geometry - 1879 - 70 pages
...in other words, all the interior angles of any rectilinear figure together with four right angles, are equal to twice as many right angles as the figure has sides. Again, parallelograms upon equal bases and with the same altitude are equal. Of all figures bounded... | |
 | Joseph Wollman - 1879 - 120 pages
...32. Corollary 1. — The interior angles of any rectilineal figure together with four right angles are equal to twice as many right angles as the figure has sides. The angles of a regular hexagon + 4 right angles = 12 right angles ; .-. The angles of a regular hexagon... | |
 | Michael McDermott - Civil engineering - 1879 - 560 pages
...for future operations. 213. All the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. Example. Interior angles A, B, C, D, E, F = n° 4 right angles, 860 Sum = n° + 360° Namber of sides... | |
 | Moffatt and Paige - 1879 - 474 pages
...are equal to twice as many right angles as the figure has sides. Therefore all the interior angles, together with all the exterior angles of the figure, are equal to all the interior angles together with four right angles (Ax. 1). From each of these equals take away... | |
 | Rolla Rouse - 1879 - 402 pages
...40 ... ... ... ... ... 103 The exterior and interior angles of an rectilineal figure, are together equal to twice as many right angles as the figure has sides, 41 ... 104 „ angles are together equal to four right angles, 42 ... ... ... ... „ The interior... | |
 | W J. Dickinson - Geometry - 1879 - 44 pages
...produced to meet, the angles formed by these lines, together with eight right angles, are together equal to twice as many right angles as the figure has sides. Same proposition. ABC is a triangle right-angled at A, and the angle B is double of the angle C. Show... | |
 | Isaac Sharpless - Geometry - 1879 - 282 pages
...But ACD+ACB = 2R; BAC+ABC+ACB = 2R. Corollary 1.—All the interior angles of a polygon are together equal to' twice as many right angles as the figure has sides, minus four right angles. Let ABODE be a polygon, and let n represent the number of its sides. Draw... | |
 | John Henry Robson - 1880 - 118 pages
...proved that " All the Interior angles of any Rectilineal figure, "together with four right angles, are equal to "twice as many right angles as the figure has " sides." If, therefore, we suppose the polygon to have n sides, All its interior angles + 4.90 .= 272.90 . -.... | |
| |
... twice as many right angles as the figure has sides. 
