 | Robert Mudie - Mathematics - 1836 - 542 pages
...the angles of all the triangles are equal to all the angles of the figure ; therefore, again, all the angles of the figure are equal to twice as many right angles wanting four as the figure has sides. We are now in possession of all the more important elementary... | |
 | Robert Mudie - Mathematics - 1836 - 524 pages
...the angles of all the triangles are equal to all the angles of the figure ; therefore, again, all the angles of the figure are equal to twice as many right angles wanting four as the figure has sides. We are now in possession of all the more important elementary... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...angle ABC, and the adjacent exterior ABD, are together equal (I. 13.) ^o two right angles ; therefore all the interior, together with all the exterior angles...figure, are equal to twice as many right angles as there are sides "" B~ of the figure ; that is, by the foregoing corollary, they are equal to all the... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...interior angle ABC, with its adjacent exterior ABD, is equal to two right angles (1. 13) ; therefore all the interior, together with all the exterior angles of the figure, are equal to twice as many right 5angles as there are sides of the figure ; that is, by the foregoing corollary, they are equal to all... | |
 | John Playfair - Euclid's Elements - 1837 - 332 pages
...as many right angles as the figure has sides, wanting four. For all the angles exterior and interior are equal to twice as many right angles as the figure has sides ; but the exterior are equal to four right angles ; therefore the interior are equal to twice as many right... | |
 | Adrien Marie Legendre - Geometry - 1837 - 376 pages
...two right angles, taken as many times, less two, as the polygon has sides (Prop. XXVI.) ; that is, equal to twice as many right angles as the figure has sides, wanting four right angles. Hence, the interior angles plus four right angles, is equal to twice as... | |
 | Charles Reiner - Geometry - 1837 - 254 pages
...vertex of these triangles = 4 rt. /.s; therefore, the sum 01 the interior angles of any polygon is equal to twice as many right angles as the figure has sides less [minus] four. M.—If the number of sides be three, four, five, six, seven, &c., what is the sum... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...you go along, as also the angles. angles, A, B, C, &c. of the figure together, and their sum must be equal to twice as many right angles as the figure has sides, wanting four right angles. But when the figure has a re-enterant angle, as F, measure the external... | |
 | Euclides - 1838 - 264 pages
...is equal* to two right angles ; therefore iV/"^--^ all the interior, together with all the *MT ^~V~ exterior angles of the figure, are equal \ \ to twice as many right angles as there \ X^r are sides of the figure ; that is, by the 1) B \ foregoing corollary, they are equal to... | |
 | Euclides - 1840 - 192 pages
...right angles. Therefore, all the external, with all the internal angles of the figure, are together equal to twice as many right angles as the figure has sides ; that is to say, according to the preceding corollary, they are equal to all the internal angles of... | |
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... twice as many right angles as the figure has sides. 
