 | Harvard University - Geometry - 1899 - 39 pages
...Corollary. The area of a rectangle is equal to the product of its base and its altitude. THEOREM IV. The area of a parallelogram is equal to the product of its base and its altitude. THEOREM V. The area of a triangle is equal to half the product of its base and its altitude.... | |
 | George Albert Wentworth - Geometry, Solid - 1899 - 246 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403.... | |
 | George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...evident by dividing the figure into squares, each BOOK IV. PLANE GEOMETKY". PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE CF CE A b ~ DA J> ' D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
 | George Albert Wentworth - Geometry - 1899 - 498 pages
...by dividing the figure into squares, each T~ BOOK IV. PLANE GEOMETRY. PROPOSITION IV. THEOREM. 400. The area of a parallelogram is equal to the product of its base by its altitude. BE OF B GE A b DAI) D Let AEFD be a parallelogram, b its base, and a its altitude.... | |
 | William James Milne - Geometry, Modern - 1899 - 258 pages
...=0= A AD F + A BED ; that is, ABCD =0= ABEF. Therefore, etc. QED MILNE'S GEOM. — 12 332. Cor. I. The area of a parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases... | |
 | Education - 1899 - 824 pages
...assumed without proof. Among the other error» in proving the second part it wa.s taken for true that the area of a parallelogram is equal to the product of its two adjacent sides. Questions 7. 8, and 9 were correctly demonstrated by nearly all (a considerable... | |
 | Metal-work - 1901 - 548 pages
...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two opposite sides AB and... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...constructed on the lines as sides. Similarly the second power of a number is called the square of the number. PROPOSITION V. — THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Given. — Let ABCD be any parallelogram, AB its base, and BE its altitude. To... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and an equal altitude.... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...303. (6) The area of any rectangle is equal to the product of its base and its altitude. § 304. (7) The area of a parallelogram is equal to the product of its base and its altitude. § 305. (8) The area of a square is equal to the square of any one of its sides. § 307.... | |
| |
The area of a parallelogram is equal to the product of its base and altitude. 
