 The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. B' ADC A' D' C' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove = — • A A'B'C'...  Solid Geometry - Page 446by John Charles Stone, James Franklin Millis - 1916 - 174 pagesFull view - About this book
 | Webster Wells - Geometry - 1894 - 400 pages
...altitudes. PROPOSITION XX. THEOREM. 531. Two tetraedrons having a triedral of one equal to a triedral of the other, are to each other as the products of the edges Including the equal triedrals. OA' x OB' X OC'' Draw CP and C'P' perpendicular to the face OA'B'.... | |
 | John Macnie - Geometry - 1895 - 386 pages
...rect. A E- (AB+ EBy^T? — Elf. PROPOSITION VIII. THEOREM. 341. Triangles that have an angle of the one equal to an angle of the other, are to each other as the rectangles contained by the sides including those angles. AD c A, D, a' Given: Two triangles, ABC,... | |
 | John Macnie - Geometry - 1895 - 390 pages
...PROPOSITION XVII. THEOREM. 561. Tetrahedrons with a trihedral angle of the one equal to a trihedral angle of the other, are to each other as the products of the edges of these trihedral angles. Given : V and F*, the volumes of two tetrahedrons having trihedral... | |
 | George Albert Wentworth - Geometry - 1895 - 458 pages
...VII. THEOREM. 374. The areas of two triangles which have an angle of the one equal to an angle of tlie other are to each other as the products of the sides including the equal angles. Let the triangles ABC and ADE have the common angle A. AA£C ABxAC To prove Proof.... | |
 | George D. Pettee - Geometry, Modern - 1896 - 272 pages
...What is the area of each of the triangles formed by the perpendicular ? PROPOSITION VIII 255. Theorem. Two triangles having an angle of one equal to an angle...each other as the products of the sides including the equal angles. Appl. Cons. Dem. Prove ABC = AB x AC ADE AD x AE Draw DC ABC = AB ADC AD ADC = AC... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...other sides, an incorrect method. PROPOSITION VIII. THEOREM 398. The areas of two triangles which have an angle of one equal to an angle of the other are...the products of the sides including those angles. GIVEN — the triangles ADE and ABC placed so that their equal angles coincide at A. area ADE AD X... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 554 pages
...sides, an incorrect method. . PROPOSITION VIII. THEOREM 398. The areas of two triangles which have an angle of one equal to an angle of the other are...the products of the sides including those angles. GIVEN — the triangles ADE and ABC placed so that their equal angles coincide at A. area ADE AD X... | |
 | Joe Garner Estill - 1896 - 186 pages
...distant from the nearest point on the circumference, is twelve units. Find the diameter of the circle. 5. Two triangles having an angle of one equal to an angle of the other are to each other as the product of the sides including the equal angles. 6. Find the ratio of the radius of a circle to the... | |
 | Joe Garner Estill - 1896 - 214 pages
...distant from the nearest point on the circumference, is twelve units. Find the diameter of the circle. 5. Two triangles having an angle of one equal to an angle of the other are to each other as the product of the sides including the equal angles. 6. Find the ratio of the radius of a circle to the... | |
 | George Albert Wentworth - Geometry - 1896 - 296 pages
...which is 1 inch ? Ex. 292. The areas of two triangles which have an angle of the one supplementary to an angle of the other are to each other as the products of the sides including the supplementary angles. Let the A ABC and A'B'C' have the A ACB and A'ffB' supplements of each other.... | |
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