 | William James Milne - Algebra - 1894 - 214 pages
...a + 6 а times a + b = a2 + ab b times a + b = ab + b1 (a + 6) times (a + 6) = a2 + 2 ab + 62 BULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 2a6-3c 4 ab + с 8 a262- 12aftc 2 a6c - Я с2 8cW- 10 a6c -3с3 Multiply... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 144 pages
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2... | |
 | George Washington Hull - Algebra - 1895 - 358 pages
...products, we 2a2 + ab - 662, Ans. have 2aJ + 06 - 66Z. From this example we derive the following RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. m2 + 2mn + w2, ^4ns. m2 — 2mn + n2 m'1 5. 6. a4 + rt'6 + a262 x*-x«... | |
 | Edward Brooks - Arithmetic - 1895 - 424 pages
...placing terms of the same order in the same column, and draw a line beneath. II. Begin at the right, and multiply each term of the multiplicand by each term of the multiplier, writing the first term of each product under the term of the multiplier used to obtain it. III. Add... | |
 | Silas Ellsworth Coleman - Arithmetic - 1897 - 180 pages
...From this example we may deduce the following rule for the multiplication of algebraic quantities : Multiply each term of the multiplicand by each term of the multiplier. * This article may be omitted at the discretion of the teacher. When the two terms of a product have... | |
 | 1897 - 358 pages
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
 | Fletcher Durell, Edward Rutledge Robbins - Algebra - 1897 - 482 pages
...Polynomials. The Distributive Law applies here as in ordinary algebraic multiplication of polynomials; hence, Multiply each term of the multiplicand by each term of the multiplier ; Simplify each term of the result, and collect. Ex.1. Multiply 31/2 + 5 1/3 by 31/2-1/3: 31/2" + 51/3... | |
 | George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1898 - 712 pages
...preceding article is derived the following principle for multiplying a multinomial by a multinomial: Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. Ex. l. Multiply -3a + 2& by 2a-36. We have -36x26 (1)... | |
 | International Correspondence Schools - Surveying - 1898 - 146 pages
...Ans. (14) In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which produces... | |
 | Seymour Eaton - 1899 - 362 pages
...Lesson No. 9. Algebraic Multiplication (Continued) To multiply one compound expression by another, multiply each term of the multiplicand by each term of the multiplier, and add results for the complete answer. To find the product of a + b and c + d. (o+6) x(c + d) = (a... | |
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X 5'" = 20"'". Hence the RULE. I. Write the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier... 
