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" RULE. — Divide the given sum by the amount of $1 for the given time and rate, and the quotient will be the present worth, and the remainder will be the discount. "
The Common-school Arithmetic: Designed for Learners of Every Class; and ... - Page 212
by Pliny Earle Chase - 1848 - 277 pages
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Orton's Lightning Calculator and Accountant's Assistant

Hoy D. Orton - Ready-reckoners - 1871 - 202 pages
...the present worth of $12.72 must be equal to the number of times $12.72 will contain 11.09, RULE. — Divide the given sum by the amount of $1 for the given rale and time, and the quotient Kill le the present worth. If the present worth 1e subtracted from...
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The American Commercial Arithmetic: For the Use of the Grand Rapids Business ...

T. A. Bryce - Business mathematics - 1873 - 370 pages
...worth of any sum, and the discount for any time, at any rate per cent., we have the following RULE. Divide the given sum by the amount of $1 for the given time and rate? and the quotient will be the present worth. From the given sum subtract the present worth,...
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Howard's California Calculator: The Newest, Quickest and Most Complete ...

C. Frusher Howard - Arithmetic - 1874 - 108 pages
...To find the present worth of any sum, and the discount for any time at any rate per cent. RDM:. — Divide the given sum by the amount of $1 for the given time and rate, and the quotient will be the present worth, and the remainder will be the discount. KXAMPLF....
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The Normal Higher Arithmetic: Designed for Common Schools, High Schools ...

Edward Brooks - Arithmetic - 1877 - 528 pages
...^95 _ $313.8! times $1 as $1.195 is contained times in $375, which is $313.81. Hence the Rule. — I. Divide the given sum by the amount of $1 for the given rate and time, to find the present worth. II. Subtract the present worth from the given sum, to find...
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The New Normal Written Arithmetic: Designed for Common Schools, Normal ...

Edward Brooks - Arithmetic - 1877 - 438 pages
...contained times $585_i-l 30=$450 Ant in $585, which is $450. Hence '" ''"•'' "'••' ' Rule. — I. Divide the given sum by the amount of $1 for the given rate and time, to find the present worth. II. Subtract the present worth from the given sum to fina...
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The Normal Union Arithmetic: Graded Course, Part 3

Edward Brooks - Arithmetic - 1877 - 232 pages
...times $5g5-1-i 30=$450 Ans in $585, which is $450. Hence •••••-. - .-..,- i. Rule. — I. Divide the given sum by the amount of $1 for the given rate and time, to find the, present worth. NOTE. — When several payments are made without interest,...
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The New Normal Written Arithmetic: Designed for Common Schools, Normal ...

Edward Brooks - Arithmetic - 1877 - 444 pages
...$1.30 is contained times $5g5_i_l 30=$450 Ana in $585, which is $450. Hence ''"" " '" " Rule. — I. Divide the given sum by the amount of $1 for the given rate and time, to find the present worth II Subtract the present worth from the given sum to find the...
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Howard's California Calculator and Golden Rule for Equation of Payments: The ...

C. Frusher Howard - Business mathematics - 1878 - 104 pages
...To find the present worth of any sum, and the discount for any time at any rate per cent. RULE. — Divide the given sum by the amount of $1 for the given time and rate, and the quotient will be the present worth, and the remainder will be the discount. EXAMPLE...
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Howard's California calculator and golden rule for equation of payments

C. Frusher Howard - Ready-reckoners - 1878 - 104 pages
...find the present worth of any sum, and the discount for any time at any rate per cent. RULE.—Divide the given sum by the amount of $1 for the given time and rate, and the quotient will be the present worth, and the remainder will be the discount. EXAMPLE...
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Howard's Art of Computation and Golden Rule for Equation of Payments for ...

C. Frusher Howard - Ready-reckoners - 1879 - 134 pages
...To find the present worth of any sum, and the discount for any time at any rate per cent. RULE. — divide the given sum by the amount of $1 for the given time and rate, and the quotient will be the present worth, and the remainder will lie the discount. EXAMPLE...
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