 | Wisconsin. Department of Public Instruction - Education - 1906 - 124 pages
...areas of two circles have the same ratio as the squares of their radii or of their diameters. 124. The area of a circle is equal to one-half the product of the circumference by the radius. Cor. The area of a circle equals irR 2 . 125. To inscribe a square... | |
 | Webster Wells - Geometry, Plane - 1908 - 208 pages
...segments, and similar sectors are those which correspond to squal central angles. PROP. XIV. THEOREM 336. The area of a circle is equal to one-half the product of its circumference and radius. Given R the radius, C the circumference, and S the area of aO. To Prove S... | |
 | Webster Wells - Geometry - 1908 - 336 pages
...segments, and similar sectors are those which correspond to equal central angles. PROP. XIV. THEOREM 336. The area of a circle is equal to one-half the product of its circumference and radius. Given R the radius, C the circumference, and S the area of aO. To Prove S... | |
 | 1911 - 864 pages
...sum of two given equilateral triangles; (b) to the difference of two given equilateral triangles. 7. Prove that the area of a circle is equal to one-half the product of its circumference and radius. 8. If a pyramid is cut by a plane parallel to its base: (a) the lateral edges... | |
 | Geometry, Plane - 1911 - 192 pages
...of the triangle AEF is three-eighths the area of the parallelogram. 8. Prove by the Method of Limits that the area of a circle is equal to one-half the product of its circumference and radius. GEOMETRY (Complete), SEPTEMBER, 1889 1. The perpendicular from the vertices... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry, Plane - 1915 - 296 pages
...27n-i+27Tr2. .-. r = n+r2. 2. Construct a circle equal in length to any number of given circles. 497. Theorem. The area of a circle is equal to one-half the product of the circumference by the radius. Given a circle with center 0. Let c denote the circumference, r the... | |
 | Mathematics - 1915 - 830 pages
...the student much with the limit idea. It is now possible to give a simple proof of the theorem : ' ' The area of a circle is equal to one-half the product of the lengths of the circumference and the radius." Let PC=perimeter of a circumscribed regular polygon.... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry - 1918 - 460 pages
...difference between two given circles. arc su c 360 u .-. arc s= • i u c = • ird. 360 360 497. Theorem. The area of a circle is equal to one-half the product of the circumference by the radius. Given a circle with center 0. Let c denote the circumference, r the... | |
 | Claude Irwin Palmer - Geometry, Solid - 1918 - 192 pages
...intercepted by a central angle of u degrees the length of the arc is — TTd. 360 § 497. Theorem. The area of a circle is equal to one-half the product of the circumference by the radius. § 498. Theorem. The area of any circle is equal to 7Tr2. § 499.... | |
 | Matilda Auerbach, Charles Burton Walsh - Geometry, Plane - 1920 - 408 pages
...diameter is constant. Cor. 2. In any circle c = 2irr. 63. The value of ir is approximately 3.14159. 64. The area of a circle is equal to one-half the product of its radius and its circumference. Cor. 1. The area of a circle is equal to IT times the square of its radius. Cor.... | |
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The area of a circle is equal to one-half the product of its circumference and radius. 
