...b> Solution : x2 v2 — + -i-= 1 a = 5, b = 3 9 25 2b2 18 Length of latus rectum = - = — a 5 293. The locus of a point which moves, so that the sum of its distances from (3, 0) and (-3, 0)is9 81 45 44 0 í+Y = 81 45 Solution : 45 81 44 81 45 The locus with the condition...

...distance from the point ( — a, 0). What does the equation become when X = 1 ? 10. Find the equation of the locus of a point which moves so that the sum of its distances from the points (a, 0), ( - a, 0) is constant and equal to 2c. 11. If the curve y2=\x + /i passes through...

...the point (1, 0) is equal to its distance from the line 1Лх + 3 = 0. 24. Determine the equation of the locus of a point which moves so that the sum of the squares of its distances from the points Q(4, 2) and R(2, - 4) = 5. 9. THE CIRCLE 9.1 CIRCLE GEOMETRY...

...the point (1, 0) is equal to its distance from the line l/ix + 3 = 0. 24. Determine the equation of the locus of a point which moves so that the sum of the squares of its distances from the points Q(4, 2) and R(2, - 4) = 5. 16. CIRCLE 16.1 CIRCLE GEOMETRY...

...squares on the sides containing the angle is greater, equal to, or less than the square on the base. Find the locus of a point which moves so that the sum of the squares on the tangents from it to two given circles is constant. 5. Define the tangent to a circle,...

...locus of the mid-points of the straight lines drawn from a given point to meet a given circle. 2. Find the locus of a point which moves so that the sum of the squares on the lines joining it to two given points is constant. 3. Triangles are described on...

...two possible positions of P. 44. The sides of a triangle have equations y = 0, Find the equation of the locus of a point which moves so that the sum of the squares of its distances from the sides of the triangle is 12. 45. Calculate the area of the triangle...

...equation when the double sign is taken plus. Hence the branch on which P is located may be defined as the locus of a point which moves so that the sum of ß times its distance from one point and * times its distance from another is constant We may therefore...

...through an angle of 45°. 5. Find the general equation to the circle referred to rectangular axes. Find the locus of a point which moves so that the sum of th« squares of its distances from the sides of an equilateral triangle is constant. 6. Find the condition...

...y2 - 14* + 21 = 0. This is the required locus. Solution i 378 ISC MATHEMATICS • Example 5 : Find the locus of a point which moves so that the sum of the squares of its distances from the two points (1,0) and (-1, 0) is 10. Solution Let A and B be the...