 | Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 214 pages
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable... | |
 | John Dozell - Arithmetic - 1827 - 190 pages
...denomination, and the second it'to the lowest term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number in. If there happen to be a... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Thomas Tucker Smiley - 1830 - 188 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term... | |
 | Daniel Adams - Arithmetic - 1830 - 280 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Arithmetic - 1831 - 198 pages
...are; and if the third term consist of several denominations, reduce it to its lowest denomination; then, Multiply the second and third terms together, and divide the product by the first term: the quotient will be the answer. Note. — The product of the second and third termsis of the... | |
 | Daniel Adams - Arithmetic - 1831 - 276 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
