...remainder, the first term of the second remainder is 126- 2 a 4 . To form the new trial divisor, we take three times the square of the part of the root already found, viz., 2a 2 — 3ba. Divide the first term of the remainder by 12a 4 , and we obtain 6 2 for the last...

...must annex two ciphers, in order to increase their square an hundredfold. Thus finally we shall obtain three times the square of the part of the root already found. With these fresh numbers we continue the operation ••• before. L IL III. 150 •0001S5193 (•057...

...increased by the last term of the root, and subtract the product from Hie last remainder. 5Hi. Take three times the square of the part of the root already found for a new trial divisor, and proceed by division to find another term of the root. 6th. Complete the...

...for the first term of the root, and subtract its cube from the given quantity. (3) Take for divisor three times the square of the part of the root already found, divide this into the leading term of the remainder, and the quotient is the next term of the root....

...from the left-hand period, and to the remainder bring down the next period for a dividend. III. Take three times the square of the part of the root already found for a trial divisor. IV. Find how many times the trial divisor is contained in the dividend, exclusive...

...used, and with the remainder unite the next three terms of the given number for a dividend. 4. Take three times the square of the part of the root already found for a trial divisor, and by this divide the dividend (rejecting the lowest two terms of the dividend)...

...the result to the root, and also to the divisor. Multiply the divisor as it now stands by the term of the root last obtained, and subtract the product from the remainder. If there are other terms remaining, continue the operation in the same manner as before. NOTE 1. Since...

...the result to the root, and also to the divisor. Multiply the divisor as it now stands by the term of the root last obtained, and subtract the product from the remainder. If there are other terms remaining, continue the operation in the same manner as before. NOTE 1. Since...

...and subtract its square from the given polynomial. Multiply the divisor as it now stands by the term of the root last obtained, and subtract the product from the remainder. If there are other terms remaining, continue the operation in the same manner as before. Note. Since all...

...of figures already obtained may be found without error by division, the divisor to be employed being three times the square of the part of the root already found. 397. The cube root of a common fraction is found by taking the cube roots of the numerator and denominator...