| Association for the improvement of geometrical teaching - Geometry, Modern - 1884 - 150 pages
...two adjoining sides of the one respectively equal to two adjoining' sides of the other, and likewise an angle of the one equal to an angle of the other ; the parallelograms are identically equal. Let ABCD, EFGH be two parallelograms having the angle ABC equal... | |
| Mathematical association - 1884 - 146 pages
...two adjoining: sides of the one respectively equal to two adjoining sides of the other, and likewise an ang:le of the one equal to an angle of the other ; the parallelograms are identically equal. Let ABCD, EFGH be two parallelograms having the angle ABC equal... | |
| Evan Wilhelm Evans - Geometry - 1884 - 170 pages
...AO parallel to BC. M ANC = ACN = CAO. ANC = CBA + BAN. Complete the proof. 24. Two triangles which have an angle of the one equal to an angle of the other, are to each other as the products of the sides in- B eluding the equal angles. See Theo. VII. BAC :... | |
| Evan Wilhelm Evans - Geometry - 1884 - 242 pages
...; hence, it is also similar to DFE. Therefore, two triangles, etc. THEOREM XI. Two triangles having an angle of the one equal to an angle of the other, and the sides about those angles proportional, are similar. Let the two triangles ABC, DEF, have the... | |
| William Kingdon Clifford - Mathematics - 1885 - 346 pages
...the famous proposition about parallel lines. 1 The first of these deductions will now show us that if two triangles have an angle of the one equal to an angle of the other and the sides containing these angles respectively equal, they must be equal in all particulars. For... | |
| Lewis Carroll - Geometry - 1885 - 318 pages
...have two adjacent sides of the one respectively equal to two adjacent sides of the other, and likewise an angle of the one equal to an angle of the other ; the Parallelograms are identically equal.' This might be a useful exercise to set ; but really it does... | |
| William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...B'C' A'B" hence AD BC A'D' X B'C' and we have ABC A' B' C' EXERCISE. Theorem. — Two triangles having an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. Suggestion. Let ADE and... | |
| Dalhousie University - 1888 - 212 pages
...parallel to the sides, the solids contained by the alternate segments of these lines are equal. 3. If two triangles have an angle of the one equal to an angle of the other, and have their areas proportional to the squares of the side* opposite these equal angles, they must... | |
| George Albert Wentworth - Geometry - 1888 - 272 pages
...homologous sides are proportional, but the homologous angles are not equal. PROPOSITION VII. THEOREM. 326. If two triangles have an angle of the one equal to an angle of the other, and the including sides proportional, they are similar. In the triangles ABC and A'B'C', let ZA=ZA',... | |
| Benjamin Franklin Finkel - Mathematics - 1888 - 518 pages
...circle; and conversely. 5. Two polygons that are similar to a third polygon ale similar to each other. 6. If two triangles have an angle of the one equal to an angle of the other, their areas are to each other as the rectangles of the sides including those angles. 7. The ratio of... | |
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