 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...and altitude 25} feet. Ans. 68.7361. CASE II. 6. When two sides and their included angle are given. Add together the logarithms of the two sides and the logarithmic sine of their included angle; from tf1is sum subtract the logarithm of the radius, which is 10, and the remainder will be the logarithm... | |
 | Charles Davies - Navigation - 1862 - 410 pages
...the contents of a triangle whose base is 15.48 chains, and altitude 9.67 chains ? Ans. 7A. IR 38P. SECOND METHOD. Measure two sides and their included...radius, which is 10, and the remainder will be the logo.ritiim of double the area of the triangle. Find, from, the table, 120=s -flog ^0125.81 . . 2.099715... | |
 | Adrien Marie Legendre - Geometry - 1863 - 464 pages
...— =- (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following K u LE . Add together the logarithms of the two sides and the...sine of their included angle ; from this sum subtract 10 ; the remainder will be the logarithm of double the area of the triangle. Find, from the table,... | |
 | Charles Davies - Navigation - 1866 - 426 pages
...15.48 chains, and altitude 9.67 chains ? Ans. IA. IR 88P. SECOND METHOD. Measure two sides and tlieir included angle. Then, add together the logarithms...radius, which is 10, and the remainder will be the loga, 20 I + log ¿(7125.81 . . 2.099715 SV 1 +log sin A 57° 25' . 9.925626 the number ansiuering... | |
 | Charles Davies - Navigation - 1866 - 448 pages
...the contents of a triangle whose base ie 15.48 chains, and altitude 9.67 chains ? Ans. JA. IR 38P. SECOND METHOD. Measure two sides and their included...the logarithmic sine of their included angle; from Üiis sum subtract the logarithm of </'« radius, which is 10, and the remainder will be the logarühm... | |
 | Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...the two sides into the natural sine of 4he included angle. And from (2) we obtain the following RULE. Add together the logarithms of the two sides and the logarithmic sine of the included angle, reject 10, and the remainder will be the logarithm of double the area of the triangle.... | |
 | Charles Davies, Adrien Marie Legendre - Geometry - 1869 - 470 pages
...— =p (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following RULE. Add together the logarithms of the two sides and the logarithmic sine of their included angle j from this sum subtract 10 ; the remainder will be the logarithm of double the area of the triangle.... | |
 | Charles Davies - Leveling - 1871 - 448 pages
...chains? Ans. 7 A. 1R. 38 P. SECOND METHOD. RULE. — Measure two sides and their included angle. TJien, add together the logarithms of the two sides and the...included angle ; from this sum subtract the logarithm of tlie radius, which is 10, and the remainder will be the logarithm ef double the area of the triangle.... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...I?, —^- (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following BULB. Add together the logarithms of the two sides and the...logarithmic sine of their included angle; from this mm tubtract 10 ; the remainder w&l be the logarithm of dm1ble the area of the triangle, find, from... | |
 | Charles P. Florent Baillairgé - Geometry - 1873 - 660 pages
...remaining the same, to determine the area for an enclosed angle=45° 1 AIIS 588.6664. (13) By Logarithms. Add together the logarithms of the two sides and the logarithmic sine of their enclosed angle ; from this »um take 10, log. of the radius, and the remainder will be the log. of... | |
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Then, add together the logarithms of the two sides and the logarithmic sine of their included angle; from this sum subtract the logarithm of the radius, which is 10, and the remainder will be the logo.ritiim of double the area of the triangle. 
