| Adrien Marie Legendre - Geometry - 1857 - 444 pages
...and altitude 25} feet. Ans. 68.7361. CASE II. 6. When two sides and their included angle are given. **Add together the logarithms of the two sides and the logarithmic sine of their included angle; from** tf1is sum subtract the logarithm of the radius, which is 10, and the remainder will be the logarithm... | |
| Charles Davies - Navigation - 1862 - 414 pages
...the contents of a triangle whose base is 15.48 chains, and altitude 9.67 chains ? Ans. 7A. IR 38P. **SECOND METHOD. Measure two sides and their included...radius, which is 10, and the remainder will be the** logo.ritiim of double the area of the triangle. Find, from, the table, 120=s -flog ^0125.81 . . 2.099715... | |
| Adrien Marie Legendre - Geometry - 1863 - 464 pages
...— =- (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following K u LE . **Add together the logarithms of the two sides and the...sine of their included angle ; from this sum subtract** 10 ; the remainder will be the logarithm of double the area of the triangle. Find, from the table,... | |
| Charles Davies - Navigation - 1866 - 428 pages
...15.48 chains, and altitude 9.67 chains ? Ans. IA. IR 88P. SECOND METHOD. Measure two sides and tlieir **included angle. Then, add together the logarithms...radius, which is 10, and the remainder will be the** loga, 20 I + log ¿(7125.81 . . 2.099715 SV 1 +log sin A 57° 25' . 9.925626 the number ansiuering... | |
| Charles Davies - Navigation - 1866 - 422 pages
...the contents of a triangle whose base ie 15.48 chains, and altitude 9.67 chains ? Ans. JA. IR 38P. **SECOND METHOD. Measure two sides and their included...the logarithmic sine of their included angle; from** Üiis sum subtract the logarithm of </'« radius, which is 10, and the remainder will be the logarühm... | |
| Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...the two sides into the natural sine of 4he included angle. And from (2) we obtain the following RULE. **Add together the logarithms of the two sides and the logarithmic sine of** the included angle, reject 10, and the remainder will be the logarithm of double the area of the triangle.... | |
| Charles Davies, Adrien Marie Legendre - Geometry - 1869 - 472 pages
...— =p (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following RULE. **Add together the logarithms of the two sides and the logarithmic sine of their included angle** j from this sum subtract 10 ; the remainder will be the logarithm of double the area of the triangle.... | |
| Charles Davies - Surveying - 1871 - 448 pages
...chains? Ans. 7 A. 1R. 38 P. SECOND METHOD. RULE. — Measure two sides and their included angle. TJien, **add together the logarithms of the two sides and the...included angle ; from this sum subtract the logarithm of** tlie radius, which is 10, and the remainder will be the logarithm ef double the area of the triangle.... | |
| Charles Davies - Geometry - 1872 - 464 pages
...I?, —^- (Trig., Art. 30), and applying logarithms, we have, hence, we may write the following BULB. **Add together the logarithms of the two sides and the...logarithmic sine of their included angle; from this** mm tubtract 10 ; the remainder w&l be the logarithm of dm1ble the area of the triangle, find, from... | |
| Charles P. Florent Baillairgé - Geometry - 1873 - 658 pages
...remaining the same, to determine the area for an enclosed angle=45° 1 AIIS 588.6664. (13) By Logarithms. **Add together the logarithms of the two sides and the logarithmic sine of their** enclosed angle ; from this »um take 10, log. of the radius, and the remainder will be the log. of... | |
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