 | Elias Loomis - Algebra - 1862 - 312 pages
...figure ; annex the result both to the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product...remainder bring down the next period for a new dividend. If the product should be greater than the dividend, diminish the last figure of the root. 5. Double... | |
 | James Bates Thomson - Arithmetic - 1862 - 436 pages
...the right of the partial divisor ; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend,...remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, &c., as before, and thus continue... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...of the three parts will be the complete divisor, which multiply by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Proceed in same way, until all the periods are brought down. EXAMPLE. Find the cube root of 111215247129.... | |
 | James Bates Thomson - Arithmetic - 1862 - 428 pages
...the right of the partial divisor; multiply the divisor thus completed by the figure last placed in the root; subtract the product from, the dividend, and to the remainder bring down t/ie next period for a new dividend. IV. Double the root already found, for a new partial divisor,... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...the quotient in the root, and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product...remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but one figure ; each of the others will contain two.... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...add the correction, and the result will be the complete divisai'. V. Multiply the. complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring flown another period for a new dividend. VI. Add together the last complete divisor, the last correction,... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...two figures of the root, and the square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product...remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period fur a new diuidend. V. Take the last complete divisor, doubling its right-hand... | |
 | George Augustus Walton - Arithmetic - 1864 - 376 pages
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considered as fens), by three for a trial... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considtred as fens), by three for a trial... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
