 | Charles Davies - Arithmetic - 1865 - 372 pages
...the root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend,...to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
 | George Augustus Walton, Mrs. Electra Nobles Lincoln Walton - Arithmetic - 1865 - 354 pages
...divisor thus obtained by the last figure of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the root figures already found for a new trial divisor, and proceed as before. NOTE I. — When a zero occurs... | |
 | W H. Wingate - 1865 - 150 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...the figure in the root and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product...remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Joseph Ray - Algebra - 1866 - 250 pages
...figure in the root, and also on the right of the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product...remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...divisor; add the correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product...from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...will be the complete divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. Extract the cube root of the following numbers.... | |
 | Charles Haynes Haswell - Measurement - 1866 - 340 pages
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a new dividend. Double this root for a divisor ; then ascertain how man' times this incomplete divisor is contained in the... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...Multiply the divisor, thus increased, by the last figure of the root; subtract the product from tJic dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...unit's place of the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before to the last... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
