The perpendicular bisectors of the sides of a triangle meet in a point. 12. The bisectors of the angles of a triangle meet in a point. 13. The tangents to a circle from an external point are equal. 14... Plane and Solid Geometry - Page 65by Isaac Newton Failor - 1906 - 418 pagesFull view - About this book
| George Albert Wentworth - Geometry - 1904 - 496 pages
...and BC, and therefore in the bisector CF. (Why ?) Ex. 25. The perpendicular bisectors of the sides of a triangle meet in a point which is equidistant from the vertices of the triangle. Let the -L bisectors EE' and DUf intersect at 0. Then 0 being in EE' is equidistant... | |
| Edward Rutledge Robbins - Geometry, Plane - 1906 - 268 pages
...drawn from any vertex to the midpoint of the opposite side. A triangle has three medians. 84. THEOREM. The bisectors of the angles of a triangle meet in a point which is equally distant from the sides. Given: A ABC, AX bisecting ZA, BY and cz the other bisectors. To Prove:... | |
| Isaac Newton Failor - Geometry - 1906 - 440 pages
...DEFINITION. O is called the incenter of the triangle ABC. 149 The perpendicular bisectors of the sides of a triangle meet in a point which is equidistant from the vertices of the triangle. PROOF. Let the -L bisectors FF' and EE' intersect in -i* 0. Then O is equidistant... | |
| Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...drawn from any vertex to the midpoint of the opposite side. A triangle has three medians. 84. THEOREM. The bisectors of the angles of a triangle meet in a point which is equally distant from the sides. Given: A ABC, AX bisecting ZA, BY and CZ the other bisectors. To Prove:... | |
| Louisiana. Department of Education - Education - 1908 - 366 pages
...the opposite sides of a parallelogram ;ire equal. 9. Prove that the bisectors of the angles of any triangle meet in a point which is equidistant from the sides of the triangle. 10. Given three points, construct a circle passing through the given points. 11. Divide a given straight... | |
| Elmer Adelbert Lyman - Geometry - 1908 - 364 pages
...Draw OF from O to the midpoint of AC, and prove OF is the perpendicular bisector of AC. 2. Show that the bisectors of the angles of a triangle meet in a point. SUGGESTIONS. Draw two bisectors, as AO and BO. These must intersect. (Why?) Join O, the point of intersection,... | |
| Grace Lawrence Edgett - Geometry - 1909 - 104 pages
...bisector of the line. 2. The perpendicular bisectors of the sides of a triangle meet in a point. 3. The bisectors of the angles of a triangle meet in a point. 4. The bisectors of two exterior angles and the bisector of the non-adjacent interior angle of a triangle... | |
| Joseph George Coffin - Vector analysis - 1911 - 308 pages
...opposite sides of a quadrilateral coincide whether the four sides be in the same plane or not. 27. The bisectors of the angles of a triangle meet in a point which trisects each of them. Employ unit vectors along two of the sides as independent vectors. The bisectors... | |
| Geometry, Plane - 1911 - 192 pages
...their perimeter have the same ratio as these radii. JUNE, 1890 (Time allowed, one hour.) 1. Prove that the bisectors of the angles of a triangle meet in a point. 2. On a given straight line AB construct a segment of a circle containing an angle equal to a given... | |
| George Clinton Shutts - Geometry - 1912 - 392 pages
...bisector of an angle of a triangle and the bisectors of the exterior angles of the two other vertices meet in a point which is equidistant from the sides of the triangle. Use loci. 9. The line joining the feet of the perpendiculars from the extremities of the base of an... | |
| |