 | Warren H. Sadler - 1888 - 426 pages
...many dollars of principal to produce $8.10 interest as $.054 is contained times in $8.10, or $150. Rule. — Divide the given interest by the interest of $1 for the given time and at the given rate. NOTE. — To find the interest of $1, divide the rate per annum into 860,... | |
 | Hoy D. Orton - Business mathematics - 1889 - 344 pages
...equal to the number of times $12.72 will contain $1.06. RULE. — Divide the given sum by the amount of $1 for the given rate and time, and the quotient will be the present worth. Jf the present worth be subtracted from the given sum, the remainder will be the discount.... | |
 | James William Nicholson - Arithmetic - 1889 - 408 pages
...contained times in $114.60, equal to $375. Formula. — Principal = Interest -h (Rate X No. of Years). RULE. — Divide the given interest by the interest of $1 for the given time and rate; the quotient -will express the number of dollars in the principal. If the amount is... | |
 | Caton's national business college, Buffalo, N.Y. - 1889 - 330 pages
...is 150 times the interest of $1 ($.054) the principal of the given interest must be 150 times §1. RULE. — Divide the given interest by the interest of $1 for the given time and at the given rate. NOTE 1. — To find the interest of (1, divide the days regarded as cents... | |
 | Warren H. Sadler, William Russell Will - Business mathematics - 1890 - 316 pages
...($8.10) is 150 times the interest of $1 ($.054) the principal of the given interest must be 150 times $1. RULE. — Divide the given interest by the interest of $1 for the given time and at the given rate. NOTE 1. — To find the interest of $1, divide the days regarded as cents... | |
 | Edward Brooks - Arithmetic - 1895 - 424 pages
...dollars as $.21 are contained $136.50 »6,.Q times in $136.50, which is $650. Hence the .21 following Rule. — Divide the given interest by the interest of $1 for the given rate and time, or divide the amount by the amount of $1. What principal will 4. Amount to $1200.50 in 8 yr. 4 mo.... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...as Int. of $1 = $.lo2 152 {s contained times iu 30.40, $30.40 -*- .152 = $200, Aus. which is $200. RULE. Divide the given interest by the interest of $1 for the given time and rate. What principal at interest will gain — 2. $105.60 in 3 yr. 8 mo. at 6% ? 3. $11.76... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...and $ 240 -7- 0.992 = $ 241.94, Ans. Hence, Rule. Divide the required proceeds by the proceeds of $ 1 for the given rate and time, and the quotient will be the face of the required note. 10. For what sum must a 3 months' note be given, that the proceeds may be... | |
 | William Seneca Sutton - 1896 - 342 pages
...da. at 1% ? Ans. $ 1,080. 12. $ 123 in 3 yr. 5 mo. at 8% ? Ans. $450. 254. To find the Principal : Divide the given interest by the interest of $1 for the given time at the given rate; multiply $1 by the quotient. FORMULAS. To find the Time. 255. To find the time... | |
 | Charles Edward White - Arithmetic - 1897 - 312 pages
...interest, it will take as many dollars to gain $60 interest as $.24 is contained times in $60, or $250. Rule. — Divide the given interest by the interest of $1 for the given time and rate. 2. What principal at 6% will amount to $310 in 4 years ? 3. What sum invested at 5%... | |
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RULE. Divide the given interest by the interest of $1 for the given rate and time, and the quotient will be the principal. 
