| Thomas Grainger Hall - 1853 - 268 pages
...the result both in the root and in the divisor. 3d. Multiply the divisor thus augmented by the new figure of the root, and subtract the product from the dividend, and to the remainder add the next period. 4th. For a new divisor, double the first two figures of the root, and find the... | |
| Daniel Leach - Arithmetic - 1853 - 622 pages
...divisor. Multiply the. complete divisor by the last figure, and subtract the product from the partial dividend, and to the remainder annex the next period for a new partial dividend. To the complete divisor add the last figure of the root for a new trial divisor.... | |
| Mathew Wilson - 1854 - 210 pages
...root and to the divisor. 6. Multiply the divisor thus increased by the figure of the root h:st found, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. To the last divisor add the last figure of the root for a new divisor, with which proceed as before... | |
| Dana Pond Colburn - Arithmetic - 1855 - 396 pages
...Multiply the true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the number standing... | |
| George Roberts Perkins - Arithmetic - 1855 - 388 pages
...the right, to the last term of the 2n COLUMN, for its next term. Multiply this term by the last found figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a NEW DIVIDEND. Proceed as before until all the periods have been brought... | |
| John Radford Young - 1855 - 218 pages
...will thus have the complete divisor. 4. Multiply the complete divisor by the last found root-term, subtract the product from the dividend, and to the remainder annex the two next terms of the polynomial ; you will thus have a second dividend. 5. Proceed now exactly as... | |
| Francis Walkingame - 1855 - 186 pages
...at least, as the divisor. The first quotient figure being thus obtained, multiply the divisor by it, subtract the product from the dividend, and to the remainder annex the following figure of the dividend ; and proceed with the operation till all the figures are brought... | |
| John Fair Stoddard - Arithmetic - 1856 - 312 pages
...divisor, to form the TRUE DIVISOR. Multiply the true divisor by the figure of the root last obtained ; subtract the product from the dividend, and to the...remainder annex the next period for a NEW DIVIDEND. To the last divisor, add the last figure of the root found , (400+50) x2 22 400x50 50s •M X 0 f —... | |
| Dana Pond Colburn - Arithmetic - 1856 - 392 pages
...Multiply the true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true, divisor and the number standing... | |
| James Stewart Eaton - Arithmetic - 1857 - 376 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before until all the periods have been employed. NOTE.... | |
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