 | George Albert Wentworth - Algebra - 1890 - 376 pages
...=am-\-an-\-ap-\-bm-\-bn-\-bp-\-cm-\-cn-}-cp. To find the product of two polynomials, therefore, Multiply every ierrn of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
 | George Albert Wentworth - Algebra - 1891 - 380 pages
...-(-p) + с ( w + i = am+aи4- ap4-6 That is, to find the product of two polynomials, ' Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
 | George Albert Wentworth - Algebra - 1891 - 550 pages
...ap + 6m + bn + ¿p + сw + cn + cp. That is, to find the product of two polynomials, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 64, In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
 | William James Milne - Algebra - 1892 - 370 pages
...-5a* — 5aж 3a2*3" 35. 36. 37. 38. Multiply 2 иs" By 4а*-ÏS :45Í? 3aГ i -5ж*+3 MULTIPLICATION. RULE. — Multiply each term of the multiplicand by...and add the partial products. 2. 3. Multiply ab + 2c 3 ж2 - (m/ By 2ab — 3c -3а&с-6с2 Product, 2a2b2+ а&с-6с2 Multiply : 4. x + y by x — y. 5.... | |
 | George W. Lilley - Algebra - 1892 - 420 pages
...i5 +10 1» -5z -25 i10 + 2 z» -г 7 г« -«i4-3x" - 15x8+ 10x2-5;r- ¿5 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have г10 - r' + 2x* - з* - 5 x* + 3 i» - ЗА... | |
 | William James Milne - Algebra - 1894 - 216 pages
...a + 6 a + 6 a times a + 6 = a2 + a6 6 times a + b = a6 + 62 (a + 6) times (a + 6) = a2 + 2 a6 + 62 RULE. Multiply each term of the multiplicand by each...of the multiplier, and add the partial products. 2. 2 а6 - 3 с 4а6 + c 8a2f>2-12a6c 2 aЬc - 3 с2 8a262- 10 a6c -3с2 Multiply : 4. x + у by x + у.... | |
 | William James Milne - Algebra - 1894 - 212 pages
...b a + b a times a + b = a1 + a6 b times a + b = a6 + 62 (a + 6) times (а + ft) = а2 4- 2 a6 + ft* RULE. Multiply each term of the multiplicand by each...term of the multiplier, and add the partial products. Z. 3. 2 a6 - 3 r ж3 - 3 x*y + Я ;ryi - у3 4 ab + rx — у 8a!b'- 12 abc x4 - 3 x3i/ + 3 tfy* -... | |
 | William James Milne - Algebra - 1894 - 214 pages
...a + 6 а times a + b = a2 + ab b times a + b = ab + b1 (a + 6) times (a + 6) = a2 + 2 ab + 62 BULE. Multiply each term of the multiplicand by each term...of the multiplier, and add the partial products. 2. 2a6-3c 4 ab + с 8 a262- 12aftc 2 a6c - Я с2 8cW- 10 a6c -3с3 Multiply : 4. x + у by x + у. 5.... | |
 | George Albert Wentworth - Algebra - 1894 - 204 pages
...+ bm + 6n + bp + cm -f- en + cp. To find the product of two polynomials, therefore, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 88. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 144 pages
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2 а... | |
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Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 
