The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw... Elements of Plane Geometry: For the Use of Schools - Page 71by Nicholas Tillinghast - 1844 - 96 pagesFull view - About this book
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 486 pages
...squares. [The solution is left to the student.] PLANE GEOMETRY PROPOSITION XIII. THEOREM 378. The areas of **two triangles which have an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles. Given A ABC and A'B'C',... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 488 pages
...vertices of an inscribed rectangle inclose a rhombus. Ex. 1067. Two parallelograms are similar when they **have an angle of the one equal to an angle of the other, and the** including sides proportional. Ex. 1068. Two rectangles are similar if two adjacent sides are proportional.... | |
| George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...triangles are similar, Given ^A'. §282 §282 A A'B'C' A'B' X A'C' (The areas of two triangles that **have an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles.) 4 AABC AB AC 1S> A A'R'r'... | |
| Education - 1913 - 396 pages
...only one If two triangles have their homologous sides proportional they are similar If two triangles **have an angle of the one equal to an angle of the other** their areas are to each other as the products of the sides including the equal angles The area of a... | |
| George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 491 pages
...Given .'.ZA = ZA'. §282 Then AABC AB * AC 111611 AA'B'C' ~ AW X A'C" (The areas of two triangles that **have an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles.) AABC AB AC But f§ = I^'... | |
| George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 500 pages
...• 1 AA'B'C' AW Proof. Since the triangles are similar, Given §282 (The areas of two triangles that **have an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles.) AABC AB AC AC (Similar... | |
| Trinity College (Dublin, Ireland) - 1913 - 568 pages
...equal either to the angle AGP or to the angle ACQ. 7. Prove that if two triangles have an angle of **one equal to an angle of the other, and the sides about** these equal angles proportional, they are similar. 8. Prove that similar polygons can he divided up... | |
| Ira Louis Reeves - Military education - 1914 - 508 pages
...5, find the area of the segment subtended by the side of a regular hexagon. 8. Theorem: The areas of **two triangles which have an angle of the one equal to an angle of the other,** are to each other as the products of the sides including those angles. 9. Problem: Through a given... | |
| Queensland. Department of Public Instruction - Education - 1914 - 284 pages
...circle is half that of the square oircumBCribed about the same circle. 8. Prove that if two triangles **have an angle of the one equal to an angle of the other** arxcl the sides about these angles proportional the triangles will be similar. 9. Two circles intersect... | |
| John Wesley Young, Albert John Schwartz - Geometry, Modern - 1915 - 248 pages
...equal to an acute angle of the other. PLANE GEOMETRY 410. THEOREM. Two triangles are similar, if they **have an angle of the one equal to an angle of the other and the** including sides are proportional. , FIG. 186. Given the A ABC and A'B'C', with ZA = Z A', and AB =... | |
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