 | John Groesbeck - 1891 - 426 pages
...per square foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...40 + 50) -=- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...(30 + 40 + 50) -4- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product... | |
 | Massachusetts - Massachusetts - 1893 - 988 pages
...one-half the product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together; the square root of the product... | |
 | William Kent - Engineering - 1895 - 1234 pages
...altitude. RULE a. Multiply half the product of two sides by the sine of the Included angle. Ri'LE 3. From half the sum of the three sides subtract each side severally; multiply together the half sum and the three remainders, and extract the square root of the product.... | |
 | Peder Lobben - Mechanical engineering - 1899 - 460 pages
...the same area. To Figure the Area of Any TriangIe when Only the Length of the Three Sides is Given. RULE. From half the sum of the three sides subtract each side separately ; multiply these three remainders with each other and the product by half the sum of the... | |
 | William Whitehead Rupert - Geometry - 1900 - 148 pages
...God, for which reason He always is God." CHAPTER V. THE AREA OF A TRIANGLE IN TERMS OF ITS SIDES. 48. RULE. — From half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders and extract the square root of... | |
 | International Correspondence Schools - Sheet-metal work - 1901 - 578 pages
...63. When the three sides of • • a triangle are given, its area is found by the following rule: Rule. — From half the sum of the three sides, subtract each side separately; find the continued product of the half sum of the sides and thc three remainders; the square... | |
 | James Sherman Hunter - Arithmetic - 1902 - 414 pages
...all very brief by canceling. To find the area of any triangle when the three sidtt only are given. RULE. — From half the sum of the three sides subtract each side severally; multiply these three remainders and the said half sum continually together ; then the square root of... | |
 | William Kent - Engineering - 1907 - 1206 pages
...altitude. RULE 2. Multiply half the product of two sides by the sine of the Included angle. RULES. From half the sum of the three sides subtract each side severally; multiply together the half sum and the three remainders, and extract the square root of the product.... | |
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RULE. From half the sum of the three sides subtract each side severally. 
