| Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...preceding right triangle, AB is the hypotenuse, and AC, the perpendicular. To find the area of a triangle. RULE. From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product... | |
| George Albert Wentworth - Geometry, Modern - 1881 - 266 pages
...figure. § 424 QED GEOMETRY. — BOOK V. EXERCISES. 1. The area of any triangle may be found as follows : From half the sum of the three sides subtract each side severally, multiply together the half sum and the three remainders, and extract the square root of the product.... | |
| Daniel W. Fish - Arithmetic - 1883 - 348 pages
...6OO ft., area. 2. Find the area of a triangle whose base is 20 ft. and each, of the other sides 15 ft RULE. — From half the sum of the three sides subtract each side separately ; multiply the half -sum and the three remainders together ; the square root of the product... | |
| Daniel W. Fish - Arithmetic - 1883 - 364 pages
...COO ft., area. 2. Find the area of a triangle whose base is 20 ft. and each of the other sides 15 ft. RULE. — From half the sum of the three sides subtract each side separately j multiply the half-sum and the three remainders together; the square root of the product... | |
| Colin Arrott R. Browning - 1884 - 274 pages
...heightTT . , - 2 area He'Sht = T5T(15) When we know the length of each side, but not the perpendicular. Rule : — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root... | |
| George Bruce Halsted - Geometry - 1885 - 389 pages
...vertex, to find the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; multiply together the half -sum and the three remainders. The square root of this product... | |
| George Bruce Halsted - Geometry - 1886 - 394 pages
...vertex, to find the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; mult1ply together the half-sum and the three remainders. The square root of tltis product... | |
| Christian Brothers - Arithmetic - 1888 - 484 pages
...— 25 = 2? 52 — 39 = 13 52 — 40 = 12 52 x 27 x 13 x 12 = 219024 Area = -v/219024 = 468 sq. yd. RULE. — From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together; and the square root of the... | |
| James William Nicholson - Arithmetic - 1889 - 408 pages
...15. 15 — 5 = 10, 15 — 12 = 3, 15 — 13 = 2. 15 X 10 X 3 X 2 = 900; v'itOO = 30, Ans. in sq. in. RULE. — From half the sum of the three sides subtract each side; then multiply the half sum and the three remainders together , and extract the square root of the product.... | |
| Thomas Baker - Railroads - 1891 - 262 pages
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. RULE. From half the sum of the three sides subtract each side severally and reserve the three remainders ; multiply the half sum continually by the three remainders, and the... | |
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