 | Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...and add these three results together for a subtrahend. 5. Subtract the subtrahend from the dividend. To the remainder bring down the next period, for a new dividend, and proceed as before. If it happens in any case, that the divisor is not contained in the dividend,... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that, when the divisor is not contained in... | |
 | Charles Davies - Algebra - 1835 - 378 pages
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Mathematics - 1836 - 488 pages
...and add these three results together for a subtrahend. 4. Subtract the subtrahend from the dividend, to the remainder bring down the next period for a new dividend, and so proceed. Arithmetical and Geometrical Progression. Any rank of numbers more than two, increasing... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...by the square of the last quotient figure, and place this product under the last ; under these write the cube of the last quotient figure, and call their...remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Benjamin Peirce - Algebra - 1837 - 300 pages
...divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Benjamin Peirce - Algebra - 1837 - 302 pages
...divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | Peirpont Edward Bates Botham - Arithmetic - 1837 - 252 pages
...partial subtrahend, which parts add together, calling their amount the total subtrahend. 5. Subtract said subtrahend from the dividend, and to the remainder bring down the next period, for another dividend. 6. To find a divisor for said dividend, square the figures in the quotient, and multiply... | |
 | Luther Ainsworth - Arithmetic - 1837 - 306 pages
...last; under all, place 'the cube of the last quotient figure ; next add these three products together, and call their sum the subtrahend ; subtract the subtrahend from the dividend, and to this remain, der bring down the next period, for a new dividend. • Q. Having thus found two figures... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
