| John Bonnycastle - 1851 - 314 pages
...Daily increase, 5 miles. PROBLEM II. The two extremes, and the common difference being given, to find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient, increased by 1, will be the number of terms required.* that the total increase, divided by the number... | |
| Charles Haynes Haswell - Engineering - 1851 - 346 pages
...strike in 12 hours 1 12X(13~-2)~78 J3ns. When the Common Difference and the Extremes are given, to find the Number of Terms. RULE.— Divide the difference of the extremes by the common difference, and add one to the quotienL EXAMPLE. — A man travelled 3 miles the first day, 5 the second, 7 the third,... | |
| Daniel Leach - Arithmetic - 1851 - 280 pages
...the basket? 314. To find the number of terms, when the extremes and common difference are known, — RULE. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, ivill be the number of terms. This rule may be represented by the formulas, thus: —... | |
| Benjamin Greenleaf - 1851 - 332 pages
...of the extremes, and the product divided by 2, the quotient will be the sum of the series. Hence the RULE. — Divide the difference of the extremes by the common difference, and add 1 to the quotient ; multiply this sum by the sum of the extremes, and half the product is the sum... | |
| Benjamin Greenleaf - Algebra - 1852 - 348 pages
...— — =n — 1. „ ,. . . L — a , ft By transposition, — - — |-l=n. r . . L — a . , 11. If the extremes are 3 and 39, and the common difference 2, what is the number of terms ? L—a 39—3 7,= -^-+!=— --- 1-1=19. Ans. 12. If the first term be 5, the last term 89, the common... | |
| Benjamin Greenleaf - Arithmetic - 1852 - 380 pages
...that the number of terms is, one more than the number of differences ; therefore 8 -j- 1 — 9, tVie number of terms. RULE. — Divide the difference of...extremes by the common difference, and the quotient increased by one will be the number of terms required. 9. If the extremes are 3 and 45, and the common... | |
| Daniel Leach - Arithmetic - 1853 - 622 pages
...the basket? 314. To find the number of terms, when the extremes and common difference are known, — RULE. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms. This rule may be represented by the formulas, thus : —... | |
| 1855 - 424 pages
...number of terme is 10 : what is the common difference ? Prob. 21. The extremes of an arithmetical series are 3 and 39, and the common difference 2: what is the number of terms? Prob. 22. Find 5 means between б and 48. Prob. 23. Find 6 means between 8 and 36. Problems of various... | |
| James Bates Thomson - Arithmetic - 1855 - 436 pages
...common difference ? GO5. To find the number of terms, when the extremes and common difference are given. Divide the difference of the extremes by the common difference, and the quotient increased by 1 -will be the number of terms. OBS. The truth of this principle is manifest from the... | |
| Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...12. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 32. If the extremes be 3 and 45, and the common difference 6. what... | |
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