 | Calvin Tracy - Arithmetic - 1840 - 316 pages
...8+1=9, the whole number of terms, or answer required. From the above we derive the following rule : RULE. — Divide the difference of the extremes by the common difference, and add one to the quotient. 2. A man commenced a journey, and traveled the first day only 4 miles ; after... | |
 | Benjamin Greenleaf - Arithmetic - 1841 - 334 pages
...basket ? Ans. 288090 miles, 2 rods. PROBLEM IIL Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by one, will be the number of terms required. 9. If the eXtremes are 3 and 45, and the common... | |
 | Arithmetic - 1841 - 200 pages
...distance 366m. •«* CASE IV. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — (') Divide the difference...extremes by the common difference, and the quotient increased by one is the number of terms required. Question. — 1. The first and last terras, and common... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...18. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the ainicer. 3-2. If the extremes be 3 and 45, and the common difference 6.... | |
 | George Roberts Perkins - Arithmetic - 1841 - 274 pages
...the first term, the last term, and the common difference, to find the number of terms, wo have this RULE. Divide the difference of the extremes by the common difference, and to the quotient add one. Examples. 1. The first term of an arithmetical progression is 5, the last... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...12. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1 , will be the answer. 32. If the extremes be 3 and 45, and the common difference 6,... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...560, and the number of terms 140.) CASE IV. The first term, last term and common difference given, to jind the number of terms. RULE. Divide the difference...extremes by the common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1. A man bought cloth in arithmetical progression,... | |
 | Nathan Daboll - 1843 - 260 pages
...and 912/. the u-hoU w. PROBLEM III. liivcR the first term, last term, and common difterenr.p to find the number of terms. RULE. Divide the difference of the extremes by the common ciifturerire, and the i|uotient increased by 1 is the nuinbei of terms. * EX AM PI. ES. I. f the extremes... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 320 pages
...31. Hence, when the extremes and common difference are given, to find the number of terms:—Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 32. If the extremes be 3 and 45, and the common difference 6, what... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 352 pages
...basket ? Ans. 288090 miles, 2 rods. PROBLEM III. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and Ike quotient increased by one, will be the number of terms required 9. If the extremes are 3 and 45,... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
