 | Samuel Webber - Arithmetic - 1812 - 260 pages
...distance 366 miles. PROBLEM 3. Given the first term, the last term, and the common difference^ to find the number of terms. % RULE.* Divide the difference of the extremes by the common dlf* By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
 | Jeremiah Joyce - Arithmetic - 1812 - 274 pages
...III. The extreme terms a and z, and common difference d being given, to find the number of terms n. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by unity is the number sought : or + i ~ n. Ex. 1. When the extremes are 4 and 106, and the... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...912/. the wholt debt. PROBLEM III. Given the first term, last term, and common difference, tc find the number of terms. RULE. — Divide the difference of the extremes by the commot difference, and the quotient increased by 1 is the number of terms EXAMPLES. 1 . If the extremes... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...A. 12. Hence, When the Extremes and Common Difference aregieeii, toßrul the Number of Term» ;— Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 17. If the extremes be 3 and 45, and the common difference 6, what... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...and 912L the wholf debt. PROBLEM III. Givea the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by 1 is the number »f terras. EXAMPLE8. 1. If the extremes be 3 and 45, and the common difference... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...andQlZl. theivhoh debt. PROBLEM HI. / ' Giyeji the first term, last term, aad common difference, to' find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by 1 is the number of terms. ; EXAMPLES. 1. If the extremes be 3 and 45, and the common difference... | |
 | Arithmetic - 1818 - 264 pages
...distance of journey 180 miles. PROBLEM III. The two extremes and the common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common diffenence, and the quotient, increased by 1, is the number of term* inquired. EXAMPLES. 1. If the... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...the. jírst term, the last term, and the common différente to find the number of term», . , , ¡ \. RULE.— "Divide the difference of the extremes by the common difference, and the quotient increased by one is the number of terms required. , . , .EXAMPLES. 1. If the extremes, be 3 and 19,... | |
 | James Maginness - Arithmetic - 1821 - 378 pages
...= l9. Ans. 2 PROBLEM 4. The extremes and common difference given, to find the sum of the series. If the extremes are 3 and 39, and the common difference 2; what is the sum of the series? By formula 4, 3 + 39 x39~3+399. Ans. ' __ 2X2 For, 0-tl=sum of 1 term =12 or ].... | |
 | Nicolas Pike - Arithmetic - 1822 - 536 pages
...1+2+3+4+5+6+7+0=— =36. 2 PROBLEM III. . . • Given the extremes and the common difference, to find ifie number of terms. RULE.* Divide the difference of the...extremes by the common difference, and the quotient increased by 1 will be the number of terms required. EXAMPLES. 1st. The extremes are 3 and 39, and... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
