 | Charles Scott Venable - Arithmetic - 1888 - 402 pages
...equals half of the product of either side by the perpendicular to it from the opposite vertex; or, from half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders ; and the square root of the product is the area. III.... | |
 | Thomas A. Rice - Accounting - 1889 - 364 pages
...Multiply three sides together. 6. To find area of triangle. — Multiply base by half the altitude. Or, from half the sum of the three sides subtract each side separately ; multiply the half sum by the three remainders, and extract square root of product. 7. To find area of ellipse. — Multiply... | |
 | John Groesbeck - 1891 - 426 pages
...foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each...Multiply the half sum and the three remainders together, and extract the square root of the product. EXAMPLES. 1. What is the area of a triangle whose sides... | |
 | George Albert Wentworth - Algebra - 1892 - 312 pages
...found as follows : From the half-sum of the sides subtract each side separately. Multiply the half-sum and the three remainders together. The square root of the product is the area of the triangle. Find the area of a triangle, having given : 147. Base 17J yds., altitude 4f yds. 148.... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...= 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product is the area. 3. How many... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product is the area. H. What is... | |
 | Massachusetts - Massachusetts - 1893 - 988 pages
...product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract each...remainders together; the square root of the product divided by 160 will give the number of acres in the field. (c) When the piece of land is in the shape... | |
 | George Albert Wentworth - 1894 - 318 pages
...found as follows : From the half-sum of the sides subtract each side separately. Multiply the half-sura and the three remainders together. The square root of the product is the area of the triangle. Find the area of a triangle, having given: 147. Base 17J yds., altitude 41 yds. 148.... | |
 | Mines and mineral resources - 1894 - 330 pages
...the sides in the proportion of 3, 4 and 5. The Base x J the perpendicular = area of triangle. From i the sum of the three sides subtract each side separately ; multiply the J sum and the three remainders together, and the square root of the product = the area. HER MAJESTY'S... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...if the three sides of a triangle are given and not the altitude, the area can be found as follows : From half the sum of the three sides subtract each...multiply the half sum and the three remainders together, and extract the square root of the product ; the remit will be the area required. 5. What is the area... | |
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RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area. 
