 | John Groesbeck - 1891 - 426 pages
...root for the first figure of the required root. Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 3. Double the root already found, for a trial divisor; find how often it is contained in the dividend,... | |
 | Oscar F. Williams - Arithmetic - 1894 - 332 pages
...square root of the greatest perfect square contained in the left hand period for the first root figure; subtract its square from the left hand period, and to the remainder bring down the next period. HL Divide the number thus obtained, exclusive of its units, by twice the... | |
 | Henry B. Maglathlin - 1894 - 370 pages
...in the left-hand period, and write it in the root; subtract the square »/ this from the left-hand period, and to the remainder annex the next period for a dividend. Take twice the root found, regarded as tens, for a trial divi«or; divide the dividend by it, and write... | |
 | George Edward Atwood - Arithmetic - 1894 - 396 pages
...period, and write its cube root for the first figure of the root. Subtract this cube from the left-hand period, and to the remainder annex the next period for a, dividend. Square the root already found, multiply the square by 3, and to the product annex two ciphers for a... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...left-hand period write its root at the right of the given number, subtract the cube from the left-hand period, and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers, and multiply this resu1t by three for a trial divisor... | |
 | Bothwell Graham - Arithmetic - 1895 - 240 pages
...of a quotient at the right of the number. Subtract the square of this root figure from the lefl-hand period, and to the remainder annex the next period for a dividend. Take twice the figure of the root found for a trial divisor; divide the dividend, omitting the last... | |
 | George Edward Atwood - Arithmetic - 1899 - 392 pages
...period, and write its cube root for the jirst figure of the root. Subtract this cube from the left-hand period, and to the remainder annex the next period for a. dividend. Square the root already found, multiply the square by 8, and to the. product annex two ciphers for... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...the given number into periods of three figures each. root. Subtract the cube of this number from the period, and to the remainder annex the next period for a dividend. 3. Square the part of the root found, multiply the product by 300, and write the result ou the left... | |
 | Edward Gideon - 1902 - 272 pages
...root for the first figure of the required root. Subtract the cube of this figure from the left-hand period, and to the remainder annex the next period, for a dividend. III. Multiply the square of the root already found, regarded as tens, by 3; find how often it is contained... | |
 | Léon Stefflre - Arithmetic - 1902 - 230 pages
...period thus formed and place it under, and its root over, such period ; 8. Subtract this cube from said period and to the remainder annex the next period for a dividend, ie, carry said remainder to the next period; e. Multiply the square of the part of the root found by... | |
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Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 
