| John Dozell - Arithmetic - 1827 - 190 pages
...denomination, and the second it'to the lowest term mentioned. Multiply the second and third numbers **together, and divide the product by the first, the quotient will be the** answer to the question in the same denomination as you left the second number in. If there happen to... | |
| Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
| Daniel Parker - Arithmetic - 1828 - 348 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then **multiply the second and third terms together, and divide the product by the first,** and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination... | |
| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
| Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Thomas Tucker Smiley - 1830 - 180 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. **Multiply the second and third terms together, and divide the product by the .first** term ; the result will be the fourth term, or answer, in the same denomination to which the third term... | |
| Daniel Adams - Arithmetic - 1830 - 282 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...operation ? A. Multiply the second and third terms together, and divide their product by the first term ; **the quotient will be the fourth term, or answer, in the same denomination** with the third term. VII . How may this process of multiplying and dividing be, in most cases, materially... | |
| Daniel Adams - Arithmetic - 1831 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
| Thomas Conkling (W.) - Arithmetic - 1831 - 275 pages
...mentioned. After the statement is thus prepared, proceed by the following Ptule for Working the Question. 1. **Multiply the second and third terms together, and divide the product by the first** term- The quotient will be the answer to the question in the same name or denomination the second term... | |
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