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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Easy Introduction to Mathematics - Page 116
by Charles Butler - 1814

The elements of arithmetic

John Dozell - Arithmetic - 1827 - 190 pages
...denomination, and the second it'to the lowest term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number in. If there happen to...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first...

The Improved Arithmetic: Newly Arranged and Clearly Illustrated, Both ...

Daniel Parker - Arithmetic - 1828 - 348 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first...

The Federal Calculator; Or, Scholar's Assistant : Containing the Most ...

Thomas Tucker Smiley - 1830 - 180 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term...

Daniel Adams - Arithmetic - 1830 - 282 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first...

Practical and Mental Arithmetic: On a New Plan, in which Mental Arithmetic ...

Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...operation ? A. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII . How may this process of multiplying and dividing be, in most cases, materially...