 | Euclides - 1855 - 270 pages
...EDF. Therefore, if two triangles, &c. QED The enunciation of this proposition may be thus simplif'ed: If two triangles have two angles of the one, equal to two angles of the other, each to each, and a side of the one equal to a side of the other similarly situated as to the equal... | |
 | John Playfair - Geometry - 1855 - 334 pages
...it is not equal to it: therefore the angle BAC is greater than the angle EDF. PROP. XXVI. THLOR. Jf two triangles have two angles of the one equal to two angles of the otIirr, each to each; and one side equal to one side, viz. either the sides adjacent to the equal anglrs,... | |
 | Euclides - 1855 - 230 pages
...the angle EBC (4): and the angle AEG is equal to the angle BEH (a); therefore the triangles AEG, BEH have two angles of the one, equal to two angles of the other, each to each, and the sides AE, EB, adjacent to the equal angles, equal to one another; wherefore they... | |
 | Cambridge univ, exam. papers - 1856 - 200 pages
...another, on the same side of it, are either two right angles, or are together equal to two right angles. 3. If two triangles have two angles of the one equal to two angles of the other, each to each, and one si ie equal to one side, via. the sides opposite to equal angles in each, then... | |
 | Euclides - 1856 - 168 pages
...BAC, and the angle ABE is equal to the angle ABC (being both right angles), the triangles ABC, ABE have two angles of the one equal to two angles of the other, and the side AB common to the two. Therefore the triangles ABC, ABE are equal, and the side AE is equal... | |
 | Peter Nicholson - Cabinetwork - 1856 - 518 pages
...parallel to CD, the alternate angles, GFE, FGH, are also equal ; therefore the two triangles GEF, HFG, have two angles of the one equal to two angles of the other, each to each ; and the side FG, adjacent to the equal angles, common ; the triangles are therefore... | |
 | Elias Loomis - Conic sections - 1857 - 242 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...consequently, the two equiangular triangles BA C, CUD, are similar figures. Cor. Two triangles which have two angles of the one equal to two angles of the other, are similar; for, the third angles are then equal, and the two triangles are equian gular (BI, p. 25,... | |
 | Euclides - 1858 - 248 pages
...to assist in the demonstration of the following propositions. PROP. 26.— THEOR. — (Important.) If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz., either the sides adjacent to the equal angles in... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
