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" Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments of the base : and conversely. "
The Elements of Euclid for the Use of Schools and Colleges: Comprising the ... - Page 352
by Euclid, Isaac Todhunter - 1867 - 400 pages
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Annual Report of the Association of Ontario Land Surveyors, Volume 17

Association of Ontario Land Surveyors - Surveying - 1909 - 254 pages
...rectangle contained by the whole and that part together with the square on the other part. 4. Prove that the square on any straight line drawn from the vertex...the rectangle contained by the segments of the base. 5. (a) If a point be taken within a circle from which there fall more than two equal straight lines...
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Annual Report, Volumes 2-3

Civil Service Commission of Canada - Civil service - 1910 - 240 pages
...right-angled triangle. Construct it. 3. To divide- a given straight line in medial section. 4. Prove that the square on any straight line drawn from the vertex...the rectangle contained by the segments of the base. 5. In a circle the angle in a segment greater than a semicircle is less than a right angle. 6. To describe...
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Myers Arithmetic for Grammar Schools

George William Myers - Arithmetic - 1912 - 410 pages
...FIGURE 1 What is the 31. One side of a regular hexagon is 36'. Find the area of the hexagon. 32. A straight line drawn from the vertex of an isosceles triangle to the middle of the base is perpendicular to the base. Find the area of a regular pentagon whose sides are...
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The Elements of Plane Geometry

Euclid - 1845 - 336 pages
...unequally at D; if the rectangle AD . DB = 128 sq. ins., find the lengths of the unequal parts. 5. The square on any straight line drawn from the vertex...isosceles triangle to the base is less than the square on one of the equal sides by the rectangle contained by the segments of the base. EXERCISES 210 (Misc.)....
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Solutions of the Exercises in Tyler's Euclid

268 pages
...on DA, AC (i. Prop. 47). .: diff. of sqs on DA, AC=sq. on AC, and sq. on DA = 2 sq. on AC. 1 64, 11. The square on any straight line drawn from the vertex of an isosceles triangle to any point in the base is less than the square on a side of the triangle by the rectangle contained...
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