 | William Smyth - Plane trigonometry - 1834 - 94 pages
...third. This case, however, may be solved by means of the known property of a right angled triangle, viz. the square of the hypothenuse is equal to the sum of the squares of the two sides. It may moreover be resolved with facility by means of the two propositions... | |
 | Abel Flint - Geometry - 1835 - 368 pages
...without finding the angles ; according to the following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE SQUARES OF THE TWO LEGS. HENCE, THE SQUARE OF THE GIVEN LEG BEING SUBTRACTED FROM THE SQUARE OF THE... | |
 | W. H. Spiller - Algebra - 1835 - 210 pages
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as the square of the hypothenuse is equal to the sum of the squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...parts of a right angled triangle may be found by the first two theorems ; or if two of the sides are given, by means of the property, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. EXAMPLES. Ex. 1. In the right angled triangle BCA, there are given... | |
 | Charles Davies - Navigation - 1837 - 342 pages
...a right-angled triangle may be found by either of the four last cases : or, if two of the sides are given, by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
 | Alexander Jamieson - Fluid mechanics - 1837 - 516 pages
...the sides DH and CE ; that is, tf=\(xy). Consequently, by the property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, we shall have (i,y =*• + «*—y)'; and by extracting the... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
 | Madras literary society - 1837 - 996 pages
...which AE is the other kg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, the square of the hypothenuse is equal to the sum of the squares of the other two sides; in the right angle triangle AEB,— BE8 -f- AE JL AB* : but as BE,... | |
 | Jeremiah Day - Geometry - 1838 - 416 pages
...are referred to. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHF.... | |
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... the square of the hypothenuse is equal to the sum of the squares of the other two sides. 
