 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...period, and write its root for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find how many times... | |
 | Joseph Ray - Algebra - 1866 - 250 pages
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times the divisor... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3rd. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Isaac Todhunter - Algebra - 1866 - 580 pages
...contained in the 1 2 6 J 7 5 6 first period ; this is the first figure in the 756 root; subtract its square from the first period, and to the remainder bring down the next period. Divide this quantity, omitting the last figure, by twice the part of the root already found, and annex... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many times this... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...number : cube this figure placed in the quotient and place its product under the first period, subtract and to the remainder bring down the next period for a dividend. Example 1st. — Extract the cube or third root of 312908547060. 6x6=36 6x3=18x6= 10800 187x7= 1309... | |
 | William Harding Girdlestone - 1867 - 368 pages
...subtracted from the lefthand period ; write this as the first figure in the root, subtract its square from the first period, and to the remainder bring down the next period. Double the first figure of the root, place it on the left of the remainder, and using it as a divisor,... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...left hand period, and place its root in the quotient; subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the square of the quotient by 300, for a. divisor; see how many times the divisor is contained... | |
 | Joseph Ray - Arithmetic - 1857 - 358 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times this divisor... | |
 | Elias Loomis - Algebra - 1868 - 386 pages
...contained in the left-hand period; its cube root is the first figure of the required root. Subtract the cube from the first period, and to the remainder bring down the second period for a dividend. 3d. Take three hundred times the square of the root already found for... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
