| Gerardus Beekman Docharty - Algebra - 1862 - 334 pages
...? Ans. 200 cavalry, 600 artillery, and 1800 foot. 40. Divide the number 46 into two parts, so thai **when the one is divided by 7, and the other by 3,** th6 quotients together may amount to 10. What are the parts ? Ans. 28 and 18. 41. From the first of... | |
| Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...3 and 1 of itself is equal to 250 ? Ans. 120. 4. Divide 77 into two such parts that if one part he **divided by 7 and the other by 3, the sum of the quotients** shall be 15. Ans. 50 and 21. 5. The sum of two numbers is 75. and their difference is equal to ^ of... | |
| Benjamin Peirce - Algebra - 1865 - 300 pages
...it is divided successively by m and by n, the sum of the quotients = a. . mn a Ans. — ! —. mj-re **13. Divide the number 46 into two parts, so that when...travelled 3£ times as much by water as on horseback, and** 2^ times as much on foot as by water. How many miles did he travel in each of these three ways ? Ans.... | |
| Isaac Todhunter - Algebra - 1866 - 614 pages
...is still due; what was the amount of the bill? 5. Divide 46 into two parts, such that if one part be **divided by 7 and the other by 3, the sum of the quotients** shall be 10. 6. A company of 266 persons consists of men, women and children; there are four times... | |
| Benjamin Peirce - Algebra - 1870 - 302 pages
...is divided successively by m and by n, the sum of the quotients = a. in na Ans. — ; — . j»-)-n **13. Divide the number 46 into two parts, so that when...of the quotients = 10. Ans. 28 and 18. 14. All my** journey ings taken together, says a traveller, amount to 3040 miles ; of which I have travelled 3£... | |
| Robert Wallace - 1870 - 164 pages
...as cavalry. How many are there in each corps ? Ans. 200 cavalry, 600 artillery, and 1,800 foot. 40. **Divide the number 46 into two parts, so that when the one is divided by 7, and the other by 3, the** quotients together may amount to 10. What are the parts? Ans. 28 and 18. 41. From the first of two... | |
| Joseph Ficklin - Algebra - 1874 - 446 pages
...what was the amount of the bill ? Ans. $140. 5. Divide 46 into two parts, such that if one part be **divided by 7 and the other by 3, the sum of the quotients** shall be 10. Ans. 28 and 18. 6. A company of 266 persons consists of men, women, and children ; there... | |
| Benjamin Peirce - 1875 - 306 pages
...that when it is divided successively by m and by n, the sum of the quotients = a. . mna Ans. —j—. **m-\-n 13. Divide the number 46 into two parts, so...travelled 3£ times as much by water as on horseback, and** 2.' f times as much on foot as by water. How many miles did he travel in each of these three ways ?... | |
| David Munn - 1876 - 216 pages
...'••' f or 5 x = GO, therefore x = 12. Hence the required number is 12. 2. Divide the number 4G **into two parts, so that when the one is divided by 7, and the other by 3, the** quotients may together amount to Let x = one part ; therefore 4 G - x - other part. Then | + ílfJ?... | |
| Edwin Pliny Seaver, George Augustus Walton - Algebra - 1881 - 304 pages
...one-half of A's. How much did each invest? 358. Separate the number 104 into two parts such that, when **one is divided by 7 and the other by 3, the sum of the quotients** may be 28. :1.VJ. Separate the number 90 into two such parts that half of the greater added to double... | |
| |