 | George Albert Wentworth - Algebra - 1891 - 380 pages
...-(-p) + с ( w + i = am+aи4- ap4-6 That is, to find the product of two polynomials, ' Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
 | George W. Lilley - Algebra - 1892 - 420 pages
...i5 +10 1» -5z -25 i10 + 2 z» -г 7 г« -«i4-3x" - 15x8+ 10x2-5;r- ¿5 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have г10 - r' + 2x* - з* - 5 x* + 3 i» - ЗА... | |
 | William James Milne - Algebra - 1894 - 214 pages
...a + 6 а times a + b = a2 + ab b times a + b = ab + b1 (a + 6) times (a + 6) = a2 + 2 ab + 62 BULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 2a6-3c 4 ab + с 8 a262- 12aftc 2 a6c - Я с2 8cW- 10 a6c -3с3 Multiply : 4.... | |
 | William James Milne - Algebra - 1894 - 216 pages
...a + 6 a times a + 6 = a2 + a6 6 times a + b = a6 + 62 (a + 6) times (a + 6) = a2 + 2 a6 + 62 RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 2. 2 а6 - 3 с 4а6 + c 8a2f>2-12a6c 2 aЬc - 3 с2 8a262- 10 a6c -3с2 Multiply... | |
 | George Albert Wentworth - Algebra - 1894 - 204 pages
...+ bm + 6n + bp + cm -f- en + cp. To find the product of two polynomials, therefore, Multiply every term of the multiplicand by each term of the multiplier, and add the partial products. 88. In multiplying polynomials, it is a convenient arrangement to write the multiplier... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 144 pages
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. Multiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2 а... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 166 pages
...Hence, for the multiplication of a polynomial by a polynomial, we have the following Rule. Midtiply each term of the multiplicand by each term of the multiplier, and find the sum of the several products. 2. Multiply Зa2 — 2 a ¿ + 4 ¿2 by 2 a — 3 ¿. Зa2—... | |
 | Wallace Clarke Boyden - Algebra - 1894 - 188 pages
...2. 3a^ -2ж +1 3я?.+ 4 ж4 + 6ж3- 4ж2 + 3x То multiply a polynomial by a polynomial, multiply the multiplicand by each term of the multiplier, and add the products. How is the first term of the product obtained ? How is the last term obtained ? The polynomials being... | |
 | George P. Lilley - Algebra - 1894 - 522 pages
...х - 25 z10 + 2 а? + 7 z6 - 8 х4 - 3 х8 - 15 ж8 + 10 хг - 5 а; -25 Explanation. Multiplying each term of the multiplicand by each term of the multiplier and connecting these results with their proper signs, we have x10 — x9 + 2 xe — x6 — 5 x* + 3 z9... | |
 | George Washington Hull - Algebra - 1895 - 358 pages
...products, we 2a2 + ab - 662, Ans. have 2aJ + 06 - 66Z. From this example we derive the following RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. m2 + 2mn + w2, ^4ns. m2 — 2mn + n2 m'1 5. 6. a4 + rt'6 + a262 x*-x« + z4 - o,36... | |
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Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 
