 ... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude.  Elements of Plane and Solid Geometry - Page 179by George Albert Wentworth - 1877 - 398 pagesFull view - About this book
 | James Howard Gore - Geometry - 1898 - 232 pages
...equal altitudes are equivalent, because they are all equivalent to the same rectangle. 253. COR. 2. Any two parallelograms are to each other as the products of their bases by their altitudes; therefore, parallelograms having equal bases are to each other as their altitudes, and parallelograms... | |
 | Webster Wells - Geometry - 1898 - 284 pages
...other as their bases. 2. Two parallelograms having equal bases are to each other as their altitudes. 3. Any two parallelograms are to each other as the products of their bases by their altitudes. PROP. V. THEOREM. '312. The area of a triangle is equal to one-half the product of its base and altitude.... | |
 | Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 468 pages
...two parallelograms having equal bases are to each other as their altitudes. 260. Cor. IV. Show that any two parallelograms are to each other as the products of their bases by their altitudes. 261. Cor. V. Can you show how to find the area of any triangle? 262. Cor. VI. Can yon show that triangles... | |
 | George Albert Wentworth - Geometry - 1898 - 266 pages
...altitudes ; triangles having equal altitudes are to each other as their bases ; any two triangles are to each other as the products of their bases by their altitudes. PROPOSITION VI. THEOREM. 371. The area of a trapezoid is equal to one-half the sum of the parallel sides multiplied... | |
 | Webster Wells - Geometry - 1898 - 264 pages
...2. Two triangles having equal bases are to each other as their altitudes. 3. Any two triangles are to each other as the products of their bases by their altitudes. PROP. VI. THEOREM. 316. The area of a trapezoid is equal to one-half the sum of its bases multiplied... | |
 | George Albert Wentworth - Geometry, Plane - 1899 - 278 pages
...each other as their altitudes; parallelograms having equal altitudes are to each other as their bases; any two parallelograms are to each other as the products...bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude. a A b BD Let... | |
 | Webster Wells - Geometry - 1899 - 424 pages
...other as their bases. 2. Two parallelograms having equal bases are to each other as their altitudes. 3. Any two parallelograms are to each other as the products of their bases by their altitudes. PROP. V. THEOREM. 312. The area of a triangle is equal to one-half the product of its base and altitude.... | |
 | George Albert Wentworth - Geometry - 1899 - 496 pages
...each other as their altitudes; parallelograms having equal altitudes are to each other as their bases; any two parallelograms are to each other as the products of their bases by their altitudes. 188 PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by... | |
 | Webster Wells - Geometry - 1899 - 450 pages
...other as their bases. 2. Two parallelograms having equal bases are to each other as their altitudes. 3. Any two parallelograms are to each other as the products of their bases by their altitudes. PROP. V. THEOREM. 312. The area of a triangle is equal to one-half the product of its base and altitude.... | |
 | William James Milne - Geometry, Modern - 1899 - 258 pages
...Cor. I. The area of a parallelogram is equal to the product of its base by its altitude. 333. Cor. II. Parallelograms are to each other as the products of their bases by their altitudes; consequently, parallelograms which have equal altitudes are to each other as their bases, parallelograms... | |
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