| Royal Military Academy, Woolwich - Mathematics - 1853
...squares of AC, CD. Wherefore, if a straight line, etc. QED PROPOSITION XI. PROB. To divide a given **straight line into two parts, so that the rectangle contained by the whole,** and one of the parts, shall be equal to the square of the other part. Upon AB describe (46. i.) the... | |
| Euclides - 1853 - 146 pages
...squares of AC, CD. Wherefore, if a straight line, &c. QED PROP. XI. — PROBLEM. To divide a given **straight line into two parts, so that the rectangle contained by the whole** and one of the parts, shall be equal to the square of the other part. Let AB be the given straight... | |
| Euclides - Geometry - 1853 - 334 pages
...AC, CD. Which was to be proved. PEOP. XI. PEOB. To divide a given straight line into two such parts, **that the rectangle contained by the whole line and one of the parts** shall be equal to the square of the other part. Let AB be the given straight line. It is required to... | |
| Euclides - Geometry - 1853 - 176 pages
...С d. Wherefore, if a straight line, &c. QED PROPOSITION XI. — PROBLEM. To divide a given straigM **line into two parts, so that the rectangle contained by the whole** and one of the parts shall be equal to the square of the other part. LET ab be the given straight line... | |
| Cambridge univ, exam. papers - 1854 - 284 pages
...therefore the difference of the parallelograms GF, EH is equal to twice the triangle KBD. 2. Divide a given **straight line into two parts so that the rectangle contained by the whole line and one of the parts** shall be equal to the square of the other part. Produce a given straight line to a point such that... | |
| William Walton, Charles Frederick Mackenzie - Mathematics - 1854 - 266 pages
...diameter, the difference of the parallelograms is equal to twice the triangle BSD. 2. Divide a given **straight line into two parts so that the rectangle contained by the whole line and one of the parts** shall be equal to the square of the other part. Produce a given straight line to a point such that... | |
| Great Britain. Committee on Education - School buildings - 1855
...described upon the other two sides of it, the angle contained by those two sides is a right angle. 3. **Divide a straight line into two parts, so that the rectangle contained by the whole** and one of the parts shall be equal to the square of the other part. Section 3. 1. The angles in the... | |
| Euclides - 1855
...are together double of the equarea of A С and С D together. PROP. XI. PROBLEM. To divide a given **straight line into two parts, so that the rectangle contained by the whole** and one of the parts, shall be equal to the square oflhe other part. Let AB be the given straight line.... | |
| Robert Potts - 1855
...divides them into two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given **straight line into two parts, so that the rectangle contained by the whole,** and one of the parts, shall be equal to the square of the other part Solve the same problem algebraically,... | |
| Henry White - 1856
...another upon one side of it are either two right angles, or are together equal to two right angles. 18 **Divide a straight line into two parts, so that the rectangle contained by the whole** and ono of the parts shall be equal to the square of the other part. 19 If two circles cut each other,... | |
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