 | Robert Simson - Trigonometry - 1827 - 546 pages
...equal to KCF, and the right angle FHC equal to the right angle FKC; therefore in the triangles FHC, FKC there are two angles of the one equal to two angles of the other, each to each ; and the side FC, which is opposite to one of the equal angles in each, is common to... | |
 | Thomas Kerigan - Nautical astronomy - 1828 - 776 pages
...opposite angle CBF, — Euclid, Book I., Prop. 29. And, since the two triangles AFD and FBC have, thus, two angles of the one equal to two angles of the other, viz., the angle AFD to the angle FBC, and the angle FAD to the angle BFC, and the side AF of the one... | |
 | James Hayward - Geometry - 1829 - 228 pages
...mO' and M'N'O' are equal. The angle N'O'M' is common to the two triangles nmO' and N'M'O'; and having two angles of the one equal to two angles of the other, the other angles must be equal, that is, the angle O'M'N' is equal to the angle O' nm ; and this intersection... | |
 | Pierce Morton - Geometry - 1830 - 584 pages
...В С, and let the line EG meet DF, or DF produced in G. Then, because the triangles ABC, DEG have two angles of the one equal to two angles of the other, each to each, they are equiangular : therefore (31.) DE : EG "АВГВС, butAB:BC::DE:EF: therefore... | |
 | William Sullivan - Ethics - 1833 - 380 pages
...it. It is a truth, for example, but not a self-evident one, that if one draw two triangles, having two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either of the sides adjacent to the equal angles,... | |
 | Thomas Perronet Thompson - Euclid's Elements - 1833 - 168 pages
...proved in all other triangles under the same conditions. Wherefore, universally, if two triangles have two angles of the one, equal to two angles of the other respectively ; &c. Which was to be demonstrated. PROPOSITION XXVII. THEOREM. — If a straight line... | |
 | Euclides - 1834 - 518 pages
...equal to KCF, and the right angle FHC equal to the right angle FKC, therefore in the triangles FHC, FKC there are two angles of the one, equal to two angles of the other, each to each ; and the side FC, which is opposite to one of the equal angles in each, is common to... | |
 | Robert Simson - Trigonometry - 1835 - 544 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC; in the triangles FHC, FKC there are two angles of the one equal to two angles of the other, and the side FC, which is opposite to one of the equal angles in each, is common to both : therefore the... | |
 | Euclid - 1835 - 540 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC ; in the triangles FHC, FKC there are two angles of the one equal to two angles of the other, and the side FC, which is opposite to one of the equal angles in each, is common to both : therefore the... | |
 | Mathematics - 1835 - 684 pages
...triangles, which are equal in every respect. PROP. 5. (Eue. i. 26, first part of.) If two triangles have two angles of the one equal to two angles of the other, each to each, and likewise the interjacent* sides equal ; their other sides shall be equal, each to... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
