 | James William Nicholson - Arithmetic - 1889 - 408 pages
...15. 15 — 5 = 10, 15 — 12 = 3, 15 — 13 = 2. 15 X 10 X 3 X 2 = 900; v'itOO = 30, Ans. in sq. in. RULE. — From half the sum of the three sides subtract each side; then multiply the half sum and the three remainders together , and extract the square root of the product.... | |
 | John Groesbeck - 1891 - 426 pages
...per square foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract...together, and extract the square root of the product. EXAMPLES. 1. What is the area of a triangle whose sides are respectively 30, 40, and 50 feet ? 30 +... | |
 | Thomas Baker - Railroads - 1891 - 262 pages
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. RULE. From half the sum of the three sides subtract each side severally and reserve the three remainders ; multiply the half sum continually by the three remainders,... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...50) -=- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product is the area. 3. How many... | |
 | Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...+ 50) -4- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product is the area. H. What is... | |
 | Massachusetts - Massachusetts - 1893 - 988 pages
...one-half the product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract...multiply the half sum and the three remainders together; the square root of the product divided by 160 will give the number of acres in the field. (c) When... | |
 | Mines and mineral resources - 1894 - 330 pages
...the sides in the proportion of 3, 4 and 5. The Base x J the perpendicular = area of triangle. From i the sum of the three sides subtract each side separately ; multiply the J sum and the three remainders together, and the square root of the product = the area. HER MAJESTY'S... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...if the three sides of a triangle are given and not the altitude, the area can be found as follows : From half the sum of the three sides subtract each...together, and extract the square root of the product ; the remit will be the area required. 5. What is the area of a triangle whose sides are, respectively,... | |
 | George Washington Hull - Arithmetic - 1895 - 404 pages
...sides of a triangle are given and not the altitude, the area can be found as follows : From half the mm of the three sides subtract each side separately ;...together, and extract the square root of the product ; the result will be the area required. 5. What is the area of a triangle whose sides are, respectively,... | |
 | Horatio Nelson Robinson - Arithmetic - 1895 - 526 pages
...= GO ; CO - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60 x 30 x 20 x 10 = 600 ft, area Ans. EULE. — From half the sum of the three sides subtract each side separately; find the continued product of the half-sum and the three remainders; the square root of this product... | |
| |
RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area. 
