 | George Edward Atwood - Arithmetic - 1899 - 392 pages
...separately, find the product of the half sum and the three remainders, and extract its square root. 431. To find the area of a trapezoid. RULE. — Multiply half the sum of the parallel sides by the altitude. 432. To find the area of a trapezium. RULE. — Multiply the diagonal... | |
 | Floyd Davis - Mining engineering - 1900 - 148 pages
...is the area of a trapezoid determined? A. The area of a trapezoid is found by multiplying one-half the sum of the two parallel sides by the perpendicular distance between them. Q. 87. What is the area of a trapezoid whose two parallel sides are 12 and 16 feet respectively, and... | |
 | Nehemiah Hawkins - Steam engineering - 1901 - 354 pages
...To find the area of a Trapezoid. NOTE. A Trapezoid is a trapezium having two of its sides parallel. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them. k Fig. 38. Let the figure be the trapezoid, the sides 7 and 5 being parallel; and 3 the perpendicular... | |
 | Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...around B's farm cost $180, what should have been the cost of that around A's, at the same rate ? 225. To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides by the altitude. 1. A floor is 25 ft. long, and its two ends are respectively 16 ft.... | |
 | William Kent - Engineering - 1907 - 1206 pages
...the sum of tile perpendiculars let fall on it from opposite angles. Area of a trapezold = product of half the sum of the two parallel sides by the perpendicular distance between them. To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum... | |
 | William Kent - Engineering - 1902 - 1204 pages
...sum of the perpendiculars let fall on it from opposite angles. Area of a trapezold = product of naif the sum of the two parallel sides by the perpendicular distance between them. To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum... | |
 | Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...Fig- 7TO FIND THE AREA OF A TRAPEZOID. A Trapezoid is a trapezium having two of its sides parallel. RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them. 62 USEFUL MEASUREMENTS. Let the figure be the trapezoid, the sides 7 and 5 being parallel ; and 3 the... | |
 | Joseph Ray - Arithmetic - 1903 - 366 pages
...25£ yd. 13. A rectangular field is 15 rd. long. What must be its width to contain 1 A. ? 10J rd. 248. To find the area of a trapezoid: Rule. — Multiply half the sum of the parallel sides by the altitude. EXPLANATION. — The base of a parallelogram having the same altitude... | |
 | Frederick Thomas Hodgson - Architecture, Domestic - 1904 - 370 pages
...feet? HX 8=336 i =714 sq.ft. Ans. Problem IV. — To find the area of a trapezoid. Rule. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having... | |
 | Joseph Gregory Horner - Engineering - 1906 - 572 pages
...area may be found by the above rule for trapeziums, but generally it is calculated by the following rule: — Multiply half the sum of the two parallel...sides by the perpendicular distance between them. AREA OF THE CIRCLE. — The area of the circle may be found by any of the following three methods :... | |
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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
