| Frank Eugene Kidder - Architecture - 1886 - 640 pages
...(ce + i 2 FJ. '9-27 = area (Fig. 27). To Jind the area of a trrtpezoicl (Fig. 28). HULK. — Multiply the sum of the two parallel sides by the perpendicular distance between them, anil divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
| John H. Macke - Carpet laying - 1891 - 244 pages
...than a right angle? If less or greater than a right angle, what is the proper definition of the angle? To find the area of a trapezoid. RULE. Multiply HALF THE SUM of the two parallel sides by the altitude of the trapezoid; that is, by the distance between the two parallel sides. Example. Find the... | |
| Frank Eugene Kidder - Architecture - 1892 - 1032 pages
...X (ce + di) F'3.27 = area (Fig. 27). To find, the area of a trapczoid (Fig. 28). RULE. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
| Mines and mineral resources - 1894 - 330 pages
...as in previous problem. Fig. 49. PROB. V 1 1 . — To find the area of a trapezoid. Multiply half of the sum of the two parallel sides by the perpendicular distance between them, and p .c the product will be the / \ area. / \ \ Example. — Let ABCD (Fig. 49) be a trapezoid. The side... | |
| George Edward Atwood - Arithmetic - 1894 - 396 pages
...separately, find the product of the half sum and the three remainders, and extract its square root. 431. To find the area of a trapezoid. RULE. — Multiply half the sum of the, parallel sides by the altitude. 432. To find the area of a trapezium. RULE. — Multiply the diagonal... | |
| Thomas Aloysius O'Donahue - Mine surveying - 1896 - 184 pages
...multiply the base by half the perpendicular. PROB. VII. To find the area of a trapezoid. Multiply half of the sum of the two parallel sides by the perpendicular...distance between them, and the product will be the area. Let ABCD (Fig. 61) be a trapezoid. The side EC = 40, Fio. 61. Pra. 62. AD = 25, and DE = 18 ; required... | |
| William Dorrance Beach - Military field engineering - 1897 - 302 pages
...the area of a rectangle. Multiply the base by the height. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them and take half the product. To find the area of a triangle. Multiply the base by the altitude and take half... | |
| Alfred John Pearce - 1897 - 202 pages
...of which is 1 yd. 10. June, 1890.— Prove that the area of a trapezoid is one-half the. product of the sum of the two parallel sides by the perpendicular distance between them. The area of a trapezoidal field is 4J ac. ; the perpendicular distance between the parallel sides is... | |
| Joshua Rose - Engines - 1899 - 480 pages
...in Fig. 94. Its altitude or height is the distance between its paralell sides, as E in the figures. To find the area of a trapezoid. Rule. Multiply half the sum of the two paralell sides by the altitude. H 0 D Fig. 94. In an ellipse the line A, Fig. 95, represents the "major,"... | |
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