 | George Willson - Arithmetic - 1836 - 202 pages
...-figure. The Fig. 7. I breadth of the rectangle is «qual to half the sum of tha two parallel sides. RULE. — Multiply half the sum of the two parallel...sides, by the perpendicular distance between them. All the figures we have considered, have been referred either to a square or to a rectangle. The area... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...are as follows, viz. AB 25, AD 34, DC 35, and BC 16 ; required its area. Am. 700.99. PROBLEM XIII. To find the area of a Trapezoid. RULE. Multiply half...perpendicular distance between them, and the product will give the area.* 1. Let ABCD be a trapezoid, the side AB=40, DC = 25, CP = 18, required the area. 40... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...are 6, 8 and 10 chains ; what is the area? Ans., 24 chains. To find the area of a trapczoid. ROLE. Multiply half the sum of the two parallel sides by...distance between them, and the product will be the area. 1. What is the area of a piece of land that is 30 chains long, 20 chains wide at one end, and 18 chains... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...rode ; what is the area ? Ans. 54.299 rods. 307. To find IKt etna «/ a trapezoid. (65) Itu ir. — Multiply half the sum of the two parallel sides by...distance between them, and the product will be the ares. 1. One of the two parallel •ides of a trapezoid is 7.5 chairs, and the other 12.25, and the... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...figure. The "05*5" breadth of the rectangle is equal to naif the sum of the two parallel sides. . ... . RULE. — Multiply half the sum of the two parallel...sides, by the perpendicular distance between them. All the figures we have considered, have been referred either to a square or to a rectangle. The area... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides being 25 and 33 and the perpendicular... | |
 | Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...The three sides of a triangle are 6, 8 and 10 chains. What is the area ? Answer, 24 chains. To fold the area of a trapezoid. RULE. Multiply half the sum...distance between them, and the product will be the area. 1. What is the area of a piece of land that, is 30 chains long, 20 chains wide at one end, and 18 chains... | |
 | Commissioners of National Education in Ireland - Measurement - 1841 - 286 pages
...and BC 16 ; required its area? Ans. 700•99. PROBLEM XIII. To find the area of a trapezoid. II u IE Multiply half the sum of the two parallel sides by...perpendicular distance between them, and the product will give the area.* 1. Let ABCD be a ED trapezoid, the side AB =40, DC =25, CP= 18; required the area 1... | |
 | William Chambers, Robert Chambers - Encyclopedias and dictionaries - 1842 - 938 pages
...area comprised within the quadrilateral. The area of a trapezoid is generally found by multiplying half the sum of the two parallel sides by the perpendicular distance between them ; the area of a trapezium may likewise be found in the same way. When it ia desired to ascertain the... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...chains 1 Am. 3207 A. 2 R. PROBLEM IV. To find the area of a Trapezoid. ' ART. 12. Rule. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. 1. Required the area of the trape- D c zoid ABCD, having given... | |
| |
To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
