 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...rods ; what is the area ? Ans. 54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by...distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5 chains and the other 12.25, and the... | |
 | James Hale - Surveying - 1829 - 124 pages
...(See Def. 32, 33, and 35, Part. 1, Sec. 1.) PROBLEM VI. To find the Area of a Trapezoid. (See Def.M.) Multiply half the sum of the two Parallel Sides by the Perpendicular Height, the Product is the Area. PROBLEM VII. To find the Area of a Trapezium. (See Def. 36 and S7.)... | |
 | John Nicholson (Civil engineer) - Building - 1830 - 240 pages
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...many acres are contained in a triangle whose sides are 30, 40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply...by the perpendicular distance between them, and the pr«' duct will be the area. Ex. How many square feet are contained in a board which is 12 feet 6 inches... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel...distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the other 12.25, and the perpendicular... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find (he. area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel...distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the other 12.25, and the perpendicular... | |
 | Zadock Thompson - Arithmetic - 1832 - 182 pages
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE.— Multiply half the sum of the two parallel sides by the perpendicular distance hetween them, and the product will he the area. , 1. One of the two parallel sides of a trapezoid is... | |
 | Francis Walkingame - 1833 - 204 pages
...product will be the area. D. Fig. 5. В DE + BF x AC That is, ! = the area. For a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them ; and half the product will be the area. (1) How many square yards of paving are in the trapezium, whose... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...as follows, viz. AB 25, AD 34, D С 35, and B С 16 ; required its area ? Ans. 700-99. PROBLEM XIII. To find the area of a Trapezoid RULE. Multiply half...perpendicular distance between them, and the product will give the area.* 1. Let A BCD be a trapezoid, the side AB = r — -¡ i 40, D С = 25, С D = \ / (\... | |
 | Abel Flint - Geometry - 1835 - 368 pages
...of the angle 28° 5' 0.47076. 105x85=8925, and 8925x0.47076=4201 the double area. pf the triangle. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, or the sum of the two parallel sides by half the perpendicular distance, the product will be the area.... | |
| |
To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
