 The sum of the interior angles of a polygon is equal to twice as many right angles as the polygon has sides, less four right angles.  Plane Geometry - Page 87by Jacob William Albert Young, Lambert Lincoln Jackson - 1916 - 312 pagesFull view - About this book
 | Charles Davies - 1874 - 464 pages
...will they be similar. For, the corresponding angles in each are equal, because any angle in F cither polygon is equal to twice as many right angles as the polygon has sides, less four right angles, divided by the number of angles (BI, P. XXVI , C. 4); and further, the corresponding sides are proportional,... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...they be similar. For, the corresponding angles in each are equal, because any angle in F( >C either polygon is equal to twice as many right angles as the polygon has sides, less four right angles, divided by the number of angles (B. I, P. XXVI , C. 4); and further, the corresponding sides are proportional,... | |
 | Edward Atkins - 1874 - 428 pages
...circle, the sum of the angles in the segments exterior to the polygon, together with two right angles, is equal to twice as many right angles as the polygon has sides. 20. Draw the common tangents to two given circles. 21. From a given point draw a straight line cutting... | |
 | Edward Atkins - 1874 - 426 pages
...circle, the stun of the angles in the segments exterior to the polygon, together with two right angles, is equal to twice as many right angles as the polygon has aides. SO. Draw the common tangents to two given circles. 21. From a given point draw a straight line... | |
 | Henry Kiddle, Thomas F. Harrison, Norman Allison Calkins - Teaching - 1875 - 294 pages
...respectively equal. 6. The sum of the three angles of a triangle is equal to two right angles. 7. The sum of the interior angles of a polygon is equal to twice as many right angles as the figure has sides, less four right angles. 8. The sum of the exterior angles of a polygon is equal to... | |
 | John Reynell Morell - 1875 - 220 pages
...given to the straight line which joins two non-consecutive summits of that polygon. THEOREM XXIX. The sum of the interior angles of a polygon is equal to twice as many right angles as the figure has sides, minus two.* Through one of the summits A of the polygon ABCDEFG, let diagonals be... | |
 | William Alexander Willock - Circle - 1875 - 196 pages
...corresponding external is equal to two right angles, the sum of all the internal and all the external is equal to twice as many right angles as the polygon has angles, or sides. If we take from this latter sum the four right angles to which the external angles... | |
 | William Guy Peck - Conic sections - 1876 - 376 pages
...polygons treated of in this work are supposed to be salient. PROPOSITION XXV. THEOREM. The sum of the angles of a polygon is equal to twice as many right...as the polygon has sides, less four right angles. Let ACDEG be a polygon and let 0 be a point within it. From 0 draw lines to each of the vertices of... | |
 | Jonathan Hyslop - Coal mines and mining - 1876 - 564 pages
...= 180°, because it is a triangle. If it be a polygon, or many-sided figure, then " the sum of all the interior angles of a polygon is equal to twice as many right angles as the figure has sides, lessened by four right angles." Thus a figure with nine sides will be = (9 X 2) —... | |
 | William Guy Peck - Conic sections - 1876 - 412 pages
...angles of each triangle is two right angles ; hence, the sum of all the angles of all the triangles is equal to twice as many right angles as the polygon has sides. But, the sum of the angles of the polygon is equal to the sum of all the angles of all the triangles... | |
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