 | Euclides - 1856 - 168 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
 | Cambridge univ, exam. papers - 1856 - 200 pages
...Prove that all the internal angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides; and that all the external angles are together equal to four right angles. In what sense are these propositions... | |
 | Elias Loomis - Conic sections - 1857 - 242 pages
...THEOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. Let ABCDE be any polygon...B, C, D, E is equal to twice as many right angles, wanting four, as the figure has sides (see next page). For, from any point, F, within it, draw lines... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has sides, less four right angles (p. 26). Hence, the interior angles plus four right angles, is equal to twice as many right angles... | |
 | William Mitchell Gillespie - Surveying - 1857 - 538 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. " Calculate... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...THKOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. Let ABCDE be any polygon...B, C, D, E is equal to twice as many right angles, wanting four, as the figure has sides (see next page). For, from any point, F, within it, draw lines... | |
 | W. Davis Haskoll - Civil engineering - 1858 - 422 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given in another... | |
 | Charles Hutton - Mathematics - 1860 - 1020 pages
...Hence it lotIons that the sum of all the inward angles of the polygon alone, A -f- В — -f. D -f. E, is equal to twice as many right angles as the figure has side*, «am¡ng the said tour right angles- Q. !•'- D. THEOREM xx. When every side of any figure... | |
 | Sir Norman Lockyer - Electronic journals - 1880 - 668 pages
...XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. In the new notation we would say that the sum of the interior angles of the polygon is equal to a number... | |
 | Elizabethan club - 1880 - 156 pages
...the obtuse angles. 3. All the angles of a rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. A floor has to be laid with tiles in the form of regular figures all equal and similar ; show what... | |
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All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
