 | George W. Lilley - Algebra - 1892 - 420 pages
...first term is 5 x2, and of the last term 8y. Hence, since the difference of the squares of two numbers is equal to the product of the sum and difference of the numbers (Art. 26), 25 x2 - 64 y* = (5 x + 8 y) (5 x - 8 y). EXAMPLE 2. Factor (5 а - 4)2 - (3 а +... | |
 | Samuel Jackson - Business mathematics - 1893 - 444 pages
...cubes — 3 x product x difference of the numbers. (5) The difference of the squares of two numbers is equal to the product of the sum and difference of the numbers. Examples. 1. 3051 = (300 + 5)3 = 3002 + 25 + 10 x 300 = 90000+ 25 + 3000= 93025. 2. 4932 =... | |
 | George P. Lilley - Algebra - 1894 - 522 pages
...first term is 5 x\ and of the last term 8 y. Hence, since the difference of the squares of two numbers is equal to the product of the sum and difference of the numbers (Art. 26), 25 x2 - 64 y2 = (5 x + 8 y) (5 x -S ij). EXAMPLE 2. Factor (5 a - 4)2 - (3 a + 4... | |
 | Emerson Elbridge White - Algebra - 1902 - 104 pages
...(2-a;)(2 + a;). 26. {ax - 3 6)(a* + 36). 32. Since a2 — 62 = (a + 6)(a — 6), the difference of two squares is equal to the product of the sum and difference of their square roots. A binomial expressing the difference of two squares is resolved into two factors... | |
 | Samuel Jackson - 1904 - 434 pages
...cubes — 3 x product x difference of the numbers. (5) The difference of the squares of two numbers is equal to the product of the sum and difference of the numbers. Examples. 1. 3052=(300 + 5)2 = 3002 + 25 + lOx 300 = 90000+ 25 + 3000= 93025. 2. 493" = (500... | |
 | Frederick Thomas Hodgson - Architecture, Domestic - 1904 - 370 pages
...is equal to the product of the sum and difference of the diameters. Therefore, the area of the ring is equal to the product of the sum and difference of the two diameters, multiplied by .7854. OF ELLIPSES Problem XI. — To find the area of an ellipse. Rule.... | |
 | Isaac Newton Failor - Geometry - 1906 - 431 pages
...a line is four times the square on half the line. 903 The square of either leg of a right triangle is equal to the product of the sum and difference of the other two sides. 904 If one acute angle of a right triangle is double the other, the square of one... | |
 | Isaac Newton Failor - Geometry - 1906 - 440 pages
...a line is four times the square on half the line. 903 The square of either leg of a right triangle is equal to the product of the sum and difference of the other two sides. , 904 If one acute angle of a right triangle is double the other, the square of one... | |
 | Frederick Thomas Hodgson - 1917 - 696 pages
...is equal to the product of the sum and difference of the diameters. Therefore, the area of the ring is equal to the product of the sum and difference of the two diameters, multiplied by .7854. OF ELLIPSES Problem XI. — To find the area of an ellipse. Rule.... | |
 | William Raymond Longley - 1927 - 510 pages
...the hypotenuse is equal to the sum of the squares of the two sides. Prove that the square of one side is equal to the product of the sum and difference of the hypotenuse and the other side. a FIG. 40. 32. Show that the area of a circular ring of outer radius... | |
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But the difference of two squares is equal to the product of the sum and difference of their roots. 
