 | Royal Military Academy, Woolwich - Mathematics - 1853 - 476 pages
...opposite to the less are given, we find the sine of the angle opposite to the greater side, and as the sine of an angle is equal to the sine of its supplement, there is no reason, without other considerations, to prefer the acute angle found by the tables to... | |
 | Charles Davies - Navigation - 1854 - 446 pages
...sine of the arc GF, which is the supplement of AF, and OH is its cosine ; hence, the sine of an arc is equal to the. sine of its supplement ; and the cosine of an arc is equal to the cosine of its supplement* Furthermore, AQ is the tangent of the arc AF, and OQ... | |
 | Charles Davies - Geometry - 1855 - 340 pages
...arc GF, which is the supplement of AF, and OH is its cosine : hence, the sine of Def1nit1onsan arc is equal to the sine of its supplement; and the cosine of an arc is equal to the cosine of its supplement-* Furthermore, AQ is the tangent of the arc AF, and OQ... | |
 | Charles Davies, William Guy Peck - Electronic book - 1855 - 592 pages
...the figure, which satisfy the conditions of the problem. The two solutions arise from the fact that the sine of an angle is equal to the sine of its supplement 20 CYCLOPEDIA OF MATHEMATICAL SCIENCE. 21 perpendicular Cd, there will be but one solu-f AM'PLI-TUDE.... | |
 | Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...sine of the arc Gt\ which is the supplement of AF, and OH is its cosine : hence, the sine of an arc is equal to the sine of its supplement ; and the cosine of an <1rc is equal to the cosine of its supplement* Furthermore, AQ is the tangent of the arc AF, and OQ... | |
 | Alfred Challice Johnson - Plane trigonometry - 1865 - 166 pages
...I. Tan. 180° = ZÍÍ = - oo*. Sec. = &c. And so on for the other quadrants. 23. To prove that — The sine of an angle is equal to the sine of its supplement, and that The cosine of an angle is equal to the cosine of its supplement, but is of different sign. О... | |
 | Thomas Kimber - Mathematics - 1865 - 302 pages
...sine of an angle was equal to the cosine of its complement, and vice versa. We will now prove that the sine of an angle is equal to the sine of its supplement, where by supplement is meant, the excess of two right angles over the angle in question. Observe in... | |
 | Joseph Allen Galbraith - Mathematics - 1866 - 132 pages
...acute, it generally admits of two solutions. From equation (1), we obtain the value of log sin B; but as the sine of an angle is equal to the sine of its supplement (Chap. II., equation (24)), it follows that to the same tabular value of log sin B corresponds two... | |
 | Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...of these equations by AB, we have PM P'M' T^=-T^r", orsin.A=sin.(180°—A) . (13) -AjU AJtJ Hence the sine of an angle is equal to the sine of its supplement. Again : dividing the other equation by AB, we have AM AM' i orcos.A=-cos.(180°—A) (14) That is,... | |
 | Richard Wormell - Mechanics - 1869 - 270 pages
...the sines of the opposite angles ; hence in the triangle AMC RF _F sin A sin ACM sin AMC But since the sine of an angle is equal to the sine of its supplement, if we write (RF) for the angle between R and F we obtain RFF sin (FF) (sin RF) ~ (sin RF) If R', F,... | |
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OH is its cosine ; hence, the sine of an arc is equal to the. sine of its supplement ; and the cosine of an... 
