| Michael McDermott - Civil engineering - 1879 - 540 pages
...angle. We will arrange Napier's rules as follows, where co. = complement of the angles or hypothenuse. **Sine of the middle part, Is equal to the product of the** tangents of the adjacent parts. Is equal to the product of the cosines of the opposite parts. Sine... | |
| George Albert Wentworth - Trigonometry - 1882 - 232 pages
...I. The sine of the middle part is equal to the product of the tāagents of the aājacent parts. Rule **II. The sine of the middle part is equal to the product of the** cosincs of the apposite parts. These Rules are easily remembered by the expressions, tan. ad. and cos.... | |
| George Albert Wentworth - Trigonometry - 1882 - 160 pages
...immediately adjacent are called adjacent parts, and the other two are called opposite parts. Rule I. **The sine of the middle part is equal to the product of the** tangents of the aAjacent parts. Rule II. The sine of the middle part is equal to the product of the... | |
| George Albert Wentworth - Trigonometry - 1884 - 330 pages
...immediately adjacent are called adjacent parts, and the other two are called opposite parts. Rule I. **The sine of the middle part is equal to the product of the** \asigents of the aAjacent parts. Rule II. The sine of the middle part is equal to the product of the... | |
| George Albert Wentworth - 1887 - 346 pages
...I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. Rule **II. The sine of the middle part is equal to the product of the** famines, of the opposite parts. These Rules are easily remembered by the expressions, tan. ad. and... | |
| Webster Wells - Trigonometry - 1887 - 200 pages
...are called the adjacent parts, and the remaining two the opposite parts. Then Napier's rules are : I. **The sine of the middle part is equal to the product of the** tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
| Webster Wells - Trigonometry - 1887 - 196 pages
...are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. **II. The sine of the middle part is equal to the product** cf the cosines of the opposite parts. 146. Napier's rules may be proved by taking each of the circular... | |
| Thomas Marcus Blakslee - Trigonometry - 1888 - 56 pages
...the complements of the opposite angles, and the complement of the hypotenuse. His rules are : RULE I. **The sine of the middle part is equal to the product of the** iangents of the adjacent parts. (4) | cos Л = cosa cos 6 = cot A cot J5|(4) I. By (Сотр. Ay.)... | |
| Edwin Pliny Seaver - Trigonometry - 1889 - 306 pages
...of a middle part is equal to the product of the tangents of the adjacent parts. (ii) The sine of a **middle part is equal to the product of the cosines of the** opposite parts* To prove these rules, let them be applied to the spherical right triangle (Fig. 69),... | |
| Canada - 1893 - 1092 pages
...figure the following Napier's principle for the solution of right-angled spherical triangles : — " **The sine of the middle part is equal to the product of the** tan" gents of the adjacent parts." 2. In a right-angled spherical triangle given the other two angles,... | |
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