 | Charles Hamilton Ashton, Walter Randall Marsh - Trigonometry - 1902 - 186 pages
...opposite parts. Then the ten formulas obtained above may be condensed into the two following rules : The sine of the middle part is equal to the product of the tangents of the adjacent parts. The sine of the middle part is equal to the product of the cosines... | |
 | George Albert Wentworth - Trigonometry - 1902 - 256 pages
...middle part is equal to the product of the tangents of the Adjacent parts. RULE II. The sine of any middle part is equal to the product of the cosines of the opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
 | George Albert Wentworth - Trigonometry - 1903 - 346 pages
...middle part is equal to the product of the tangents of the &Ajacent parts. RULE II. The sine of any middle part is equal to the product of the cosines of the opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
 | George Albert Wentworth, George Anthony Hill - Logarithms - 1903 - 348 pages
...middle part is equal to the product of the tangents of the Adjacent parts. RULE II. The sine of any middle part is equal to the product of the cosines of the opposite parts. These rules are easily remembered by the expressions tan. ad. and cos. op. The correctness... | |
 | Daniel Alexander Murray - 1906 - 472 pages
...the middle part, and o, 6, are opposite parts. Napier's rules of circular parts are as follows : I. The sine of the middle part is equal to the product of the tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
 | Daniel Alexander Murray - Spherical trigonometry - 1908 - 132 pages
...the middle part, and a, b, are opposite parts. Napier's rules of circular parts are as follows : I. The sine of the middle part is equal to the product of the tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
 | Daniel Alexander Murray - Plane trigonometry - 1908 - 358 pages
...adjacent parts, thus getting ten sets in all. Napier'' s rules of circular parts are as follows : I. The sine of the middle part is equal to the product of the tangents oj the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
 | Levi Leonard Conant - Trigonometry - 1909 - 316 pages
...the opposite parts. Napier's rules for the solution of spherical right triangles are as follows : 1. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. The sine of the middle part is equal to the product of the cosines... | |
 | Leslie Leland Locke - Mathematics - 1909 - 366 pages
...complement of each part is to be taken rather than the part. Napier's Rules of circular parts : Stn of middle part is equal to the product of the cosines of the opposite parts, or equal to the product of the tangents of the adjacent parts. It is seen that omitting... | |
 | Arthur Graham Hall, Fred Goodrich Frink - Trigonometry - 1910 - 204 pages
...I. The sine of the middle part is equal to the product of the tangents of the two adjacent parts ; II. The sine of the middle part is equal to the product of the cosines of the two opposite parts. The alliterative element in the device is obvious. The validity of the rules appears only from the... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
